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Wittaler [7]
3 years ago
6

Please tell me the answer

Mathematics
2 answers:
balandron [24]3 years ago
8 0
The answer is -6. 
The distance between 36 and -114 is equal to 150. 
150/25=6, but it must be negative to get to -114. 
36-150=-114. 
goblinko [34]3 years ago
7 0
Answer: -6

hope this helps
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Need help on my math homework
scoray [572]

200 +6m = 500-6m

add 6m to each side

200+12m = 500

subtract 200 from each side

12m = 300

divide both sides by 12

m = 300/12 = 25

 25 minutes


 check:

200+ 25*6 = 200 +150 = 350

500 - 25*6 = 500-150 = 350


3 0
3 years ago
a store is having a 30% off sale on their whole store a sweater costs 245$ what will it cost after the 30% was taken off​
pentagon [3]

Answer:

$171.50

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Ok im tired of asking this <br> Ok i need both questions
Murrr4er [49]

Answer:

Answer 1:

5/8 = 2.5/4 so its 2.5 months

Answer 2: The decimal repeats as when you divide by 2 you get 4.5/8, which is 0.5625.

Step-by-step explanation:

1/4=2/8, so continue that on until you get the answer.

5/8÷1/4

5.8·4/1=

20/8=2.5

9/16=

9÷16=

0.5625

5 0
3 years ago
An advertisement claims that Fasto Stomach Calm will provide relief from indigestion in less than 10 minutes. For a test of the
nalin [4]

Answer:

z=\frac{9.25-10}{\frac{2}{\sqrt{35}}}=-2.219  

p_v =P(z  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly lower than 10 minutes.    

Step-by-step explanation:

Data given and notation  

\bar X=9.25 represent the sample mean  

\sigma=2 represent the population standard deviation

n=35 sample size  

\mu_o =10 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 10 minutes, the system of hypothesis would be:  

Null hypothesis:\mu \geq 10  

Alternative hypothesis:\mu < 10  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{9.25-10}{\frac{2}{\sqrt{35}}}=-2.219  

P-value  

Since is a left tailed test the p value would be:  

p_v =P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly lower than 10 minutes.    

6 0
4 years ago
At one store, a DVD is on sale for 25% off regular price of $26.99. At another store, the same DVD is on sale for 30% off regula
Serjik [45]

Answer:

A

Step-by-step explanation:

6 0
4 years ago
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