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Vilka [71]
3 years ago
14

2. What are the first two

Mathematics
2 answers:
Alik [6]3 years ago
8 0

Answer:

Third option

Step-by-step explanation:

2-4 6 8 10 12

3- 6 9 12

common multiples 6&12

alexdok [17]3 years ago
7 0

Answer:

6 and 12 is the answers

Step-by-step explanation:

hope this help enjoy your day:)

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What is 57 + -4 + 9<br>​
ehidna [41]

Answer:

Step-by-step explanation:

57-4=53

53+9=62

6 0
3 years ago
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A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase
Xelga [282]

Answer:

\mathbf{S(t)=200(\frac{105}{100})^{x}}

\mathbf{A(t)=40(\frac{98}{100})^{x}}

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

Step-by-step explanation:

<h3>The predicted number of students over time, S(t) </h3>

Rate of increment is 5% per year.  

A function 'S(t)' which gives the number of students in school after 't' years.  

S(0) means the initial year when the number of students is 200.

S(0) = 200  

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.  

S(1) = 200 + 5% of 200 = 200+\frac{5}{100}\time200 = 200(1+\frac{5}{100}) = 200(\frac{105}{100})  

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)  

S(2) = S(1) + 5% of S(1) = \textrm{S}(1)(\frac{105}{100}) = 200(\frac{105}{100})(\frac{105}{100}) = 200(\frac{105}{100})^{2}  

.  

.  

.  

.  

.  

Similarly \mathbf{S(x)=200(\frac{105}{100})^{x}}  

<h3>The predicted amount spent per student over time, A(t) </h3>

Rate of decrements is 2% per year.  

A function 'A(t)' which gives the amount spend on each student in school after 't' years.  

A(0) means the initial year when the number of students is 40.  

A(0) = 40  

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.  

A(1) = 40 + 2% of 40 = 40-\frac{2}{100}\time40 = 40(1-\frac{2}{100}) = 40(\frac{98}{100})  

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)  

A(2) = A(1) + 2% of A(1) = \textrm{A}(1)(\frac{98}{100}) = 40(\frac{98}{100})(\frac{98}{100}) = 40(\frac{98}{100})^{2}  

.  

.  

.  

.  

.  

Similarly \mathbf{A(x)=40(\frac{98}{100})^{x}}  

<h3>The predicted total expense for supplies each year over time, E(t)</h3>

Total expense = (number of students) ×  (amount spend on each student)

E(t) = S(t) × A(t)

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

\mathbf{E(t)=8000(\frac{10290}{10000})^{x}}

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

6 0
3 years ago
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is walking at a constant speed of 2.5 miles per hour. How far can she walk in 8 ​hours? Complete the table and plot the points t
lapo4ka [179]

Answer:

she can walk 20 miles in 8 hours if she walks st a constant speed of 2.5 miles per hour

4 0
3 years ago
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(2x2 − 5x)(4x2 − 12x + 10)<br><br> multiply
frez [133]
Is this 2x to the power of 2?
if it is then this is easy
list it out (just to show you how its solved)
2x^2*4x^2
2x^2*(-12x)
2x^2*10
then list the other one
-5x*<span>4x2
</span>-5x*(-12x)
-5x*10
so the whole answer is
8x^4+(-24x^3)+(-20x^3)+20x^2+60x^2+(-50x)
7 0
4 years ago
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The surface area of two hemispheres are in the ratio 64: 121. Find the ratio of<br> their radii
Blababa [14]

Answer:

5:7

Step-by-step explanation:

Let the radius of first hemisphere be 'r' units

Let the radius of second hemisphere be 'R' units

2 x \piπ x r^2 / 2 x \piπ x R^2 = 25 / 49

r^2 / R^2 = 25 / 49

r / R = 5 / 7

the ratio of radii is 5:7.

8 0
3 years ago
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