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Sveta_85 [38]
4 years ago
11

I have two fair spinners. The first has the numbers 1, 2, 3 and 4. The second has the numbers 2, 3, 4 and 5. I spin both spinner

s and multiply the scores. What is the probability that the number I get is odd?
Mathematics
1 answer:
Snezhnost [94]4 years ago
3 0

Step-by-step explanation:

There are 4 * 4 = 16 outcomes from spinning these spinners. You get an odd number by multiplying an odd number by an odd number. Since there are 2 odd numbers on both spinners the successful outcomes are 2 * 2 = 4 so probability is 4 / 16 = 1 / 4.

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Factor u^2-9<br><br> pls helpp im taking the test rn
IgorLugansk [536]

Answer:

(u+3)(u-3)

Step-by-step explanation:

u²-9 = u²-3²

a²-b²=(a+b)(a-b)

u²-3²=(u+3)(u-3)

8 0
3 years ago
Read 2 more answers
Alyssa wants to tile a room with an área of 480 square feet.The width of the room is 12 feet.What is the length of the room?
AfilCa [17]

Answer:

40

Step-by-step explanation:

You do 480 divided by 12

3 0
3 years ago
A canister is dropped from a helicopter 500m above the ground. Its parachute does not open, but the canister has been designed t
solmaris [256]

Answer:

The impact speed 98.995 m/s is less than 100 m/s and the canister will not burst.

Step-by-step explanation:

A function<em> F</em> is called an antiderivative of <em>f</em> on an interval <em>I</em> if F'(x) = f(x) for all x in <em>I.</em>

Recall that if the object has position function s=f(t), then the velocity function is v(t)=s'(t). This means that the position function is an antiderivative of the velocity function. Likewise, the acceleration function is a(t)=v'(t), so the velocity function is an antiderivative of the acceleration.

An object near the surface of the earth is subject to a gravitational force that produces a downward acceleration denoted by g. For motion close to the ground we may assume that g is constant, its value being about 9.8 \:{\frac{m}{s^2}}.

We know that the acceleration due to gravity is given by

a(t)=-9.8

and the antiderivative is velocity

v(t)=\int a(t)\,dt\\v(t)=\int -9.8\,dt\\v(t)=-9.8t +C

We know that the canister was dropped, so the initial velocity at t = 0 is zero, this fact let us know the value of C.

v(0)=9.8(0)+C\\C=0

The antiderivative of velocity is the position

s(t)=\int v(t) \, dt\\s(t)=\int -9.8t \, dt\\s(t)=-4.9t^2+C

To find the value of the constant C, we know that the height was 500 m at t  = 0, this means s(0)=500

500=-4.9(0)^2+C\\C=500

s(t)=-4.9t^2+500

Using the fact that at the time of impact the height s(t) is zero we can compute the total time of the fall:

s(t)=-4.9t^2+500=0\\\\-4.9t^2=-500\\\\t^2=\frac{5000}{49}\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\t=\sqrt{\frac{5000}{49}},\:t=-\sqrt{\frac{5000}{49}}

A negative time does not make sense, so we only take as a possible solution

t=\sqrt{\frac{5000}{49}}=\frac{50\sqrt{2}}{7}\approx 10.102

Now the final velocity is

v(\frac{50\sqrt{2}}{7})=-9.8(\frac{50\sqrt{2}}{7})\approx -98.995

The impact speed 98.995 m/s is less than 100 m/s and the canister will not burst.

5 0
4 years ago
7. $6,000 is invested in an account that earns 4.5% annual interest, compounded quarterly. What is the
Dafna11 [192]

Answer:

The value of account after 8 years is $8580  

Step-by-step explanation:

Given in question as :

The principal that invested in an account = $6,000

The annual interest rate  compounded quarterly = 4.5%

Time period = 8 years

Now from compound Interest method for quarterly .

Amount = Principal ( 1 + \frac{Rate}{4 \times 100})^{4 \times Time}

Or,Amount = $6,000 ( 1 + \frac{4.5}{4 \times 100})^{4 \times 8}

Or, Amount = $6,000 (1.430)

∴ Amount = $8580  

Hence the value of account after 8 years is $8580   Answer

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11111nata11111 [884]

Answer:

Student a is 28

Student b is 33

5 0
3 years ago
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