Answer:
1. a. Q° = 95°
b. a = 20.3; b = 19.3
2. p = 36; q = 14.4
Step-by-step explanation:
Question 1:
Recall: The Exterior Angle Theorem of a Triangle states that the size of the exterior angle of a triangle equals the sum of the two sizes of the two opposite angles of the triangle.
a. Based on the theorem,
Q° = 41° + 54° = 95°
b.
✔️122° = 4a + 2a (exterior angle theorem)
122 = 6a
Divide both sides by 6
122/6 = a
a = 20.3
✔️122° + 3b = 180° (angles on a straight line)
3b = 180 - 122
3b = 58
b = 58/3
b = 19.3
Question 2:
Recall: Opposite angles of a parallelogram are equal while adjacent/consecutive angles are supplementary.
✔️2p + 3p = 180° (adjacent angles)
5p = 180
p = 180/5
p = 36
✔️2p = 5q (opposite angles)
Plug in the value of p
2(36) = 5q
72 = 5q
72/5 = q
q = 14.4
Answer:
3 cups per bag
Step-by-step explanation:
I AM SMART
Answer:
C)78.5
Step-by-step explanation:
∠BOZ = X
∠WOB = 7X - 4
X + 7X -4 = 180 {STRAIGHT LINE }
8X = 180 + 4
8X = 184
X = 184/8
X = 23
∠WOB = 7X - 4 = 7*23 - 4 = 161 - 4 = 157
OA bisects ∠WOB. So, ∠WOA =∠AOB
∠AOB = 1/2 of ∠WOB = 157/2 = 78.5
Y= 1/3x -4 in slope intercept form:)
Just divide 21/1/3 and that number multiplied by 4
