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Komok [63]
4 years ago
15

How does work affect energy between objects so it can cause a change in the form of energy?

Chemistry
1 answer:
Sloan [31]4 years ago
4 0
Work can transfer entertainment between objects and cause a change in the amount of total energy. Work can also transfer energy between objects and cause a change in the form of energy .
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Which of the following statements is true of an aqueous solution of sodium chloride?
Ilya [14]

Answer:

What are the statements please

Explanation:

4 0
3 years ago
The oceanic crust is mostly associated with the —————.
Lilit [14]
I think it would the hydrosphere
4 0
3 years ago
Convert 5.00 moles of carbon to grams. Be sure to report your answer with the correct significant figures.
sergij07 [2.7K]

1 moles Carbon to grams = 12.0107 grams

2 moles Carbon to grams = 24.0214 grams

3 moles Carbon to grams = 36.0321 grams

4 moles Carbon to grams = 48.0428 grams

5 moles Carbon to grams = 60.0535 grams

6 moles Carbon to grams = 72.0642 grams

7 moles Carbon to grams = 84.0749 grams

8 moles Carbon to grams = 96.0856 grams

9 moles Carbon to grams = 108.0963 grams

10 moles Carbon to grams = 120.107 grams

8 0
3 years ago
A mixture of gases has 0.3000 mol of CO2, 0.2706 mol of SO2 and 0.3500 mol of water vapor. The total pressure of the mixture is
notka56 [123]

Answer:

Partial pressure SO₂ → 0.440 atm

Explanation:

We apply the mole fraction concept to solve this:

Moles of gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 0.3 moles of CO₂ + 0.2706 moles of SO₂ + 0.35 moles H₂O

Total moles = 0.9206 moles

Mole fraction SO₂ = 0.2706 moles / 0.9206 moles → 0.29

Now, we can know the partial pressure:

0.29 = Partial pressure SO₂ / Total pressure

0.29 = Partial pressure SO₂ / 1.5 atm

0.29 . 1.5atm = Partial pressure SO₂ → 0.440 atm

8 0
4 years ago
A buffer is made by dissolving H3PO4 and NaH2PO4 in water.
xeze [42]

Answer:

(a) H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)

(b) OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)

Explanation:

The equation for your buffer equilibrium is:

H₃PO₄(aq) + H₂O(ℓ) ⇌ H₃O⁺(aq)+ H₂PO₄⁻(aq)

(a) Adding H₃O⁺

The hydronium ions react with the basic dihydrogen phosphate ions.

H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)

(b) Adding OH⁻

The OH⁻ ions react with the more acidic hydronium ions.

OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)

4 0
3 years ago
Read 2 more answers
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