When orthobromoanisole is treated with sodamide (NaNH₂) and ammonia (NH₃), benzyne is formed and the tripple bond is formed between C₂-C₃ carbon atoms of benzene ring. Then NH₂⁻ can attack at ortho position as well as meta position.
The reaction takes place in three steps. Step-1:The amide NH₂⁻ ion attacks the H
-atom that is ortho to C3
, generating a carbanion. Step-2:Loss of Br
- to form a benzyne intermediate.Step-3:Addition of NH₂⁻ ion. The strain caused by a triple bond in a benzene ring can be relieved by a nucleophilic addition of NH₂⁻.
Two isomeric products are formed: (1) <em>o</em>-methoxyaniline and (2) <em>m</em>-methoxyaniline. The structures of both the isomeric products are given in diagram.
Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as
For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions
(b) For 200°C and 1.1 atm,
Then the concentration in mg/m3 is
Simple really, when you...
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