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lorasvet [3.4K]
3 years ago
10

Through his investigation, Nathanial identified when equal forces are applied to an object, the motion of the object does not ch

ange. He started a data table to record the evidence from his investigation. Which further evidence can Nathanial use to support his findings?
67 N in row one and 110 N in row two
120 N in row one and 67 N in row two
115 N in row one and 65 N in row two
100 N in row one and 65 N in row two
Chemistry
2 answers:
Daniel [21]3 years ago
8 0

Answer:

A is the answer

Explanation:

iris [78.8K]3 years ago
7 0
67 N in row one and 110 N in row two
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Imagine that you helped to discover a new element:
bulgar [2K]

Answer:

Proton = 119

Electron = 119

Neutron = 183

Explanation:

Mass number (A) = 302

Atomic number (Z) = 119

Proton = atomic number = 119

Since there is no charge on the element, it means the element is neutral.

Therefore,

Electron = proton = 119

Mass number = proton + Neutron

Neutron = Mass number — proton

Neutron = 302 — 119

Neutron = 183

7 0
3 years ago
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The sun melts a popsicle. is what type pf transfer
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Answer:

heat?

Explanation:

the sun warms the popsicle, therefore melting th popsicle.

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3 years ago
Which sequence of group 18 elements demonstrates a gradual decrease in forces of attraction
DanielleElmas [232]

Answer: Xe, Kr, Ar, Ne

Explanation:

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3 years ago
If an insufficient amount of liquid unknown had been used, how would this have effected the value of the experimental molar mass
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4 years ago
The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests tha
lakkis [162]

Answer:

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

Explanation:

Volume of the radiator = 3.6 L

Percentage of antifreeze = 60%

Total volume of anti freeze in radiator = 60% of 3.6 L :

\frac{60}{100}\times 3.6 = 2.16 L

Percentage of water= 40%

Given,optimal cooling of the engine is obtained with only 50% antifreeze.

So, now we want to reduce the percentage of antifreeze from 60% to 50 %

Volume of coolant removed = x

Volume of water added = x

Volume of anti freeze removed = 60% of(x) = 0.6x

Volume of antifreeze left in radiator  =50% of 3.6 L = \frac{50}{100}\times 3.6=1.8 L

1.8 Liter is the desired volume of the antifreeze.

Total volume - Removed volume = desired  volume

2.16 L - 60% of( x) = 1.8 L

2.16 L-0.6x=1.8 L

x=\frac{2.16 l- 1.8 L}{0.6}=0.6 L

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

4 0
4 years ago
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