or 
At the point/angle E:
- the adjacent side(side <u>next to</u> the point/angle) is ED
- the opposite side(side of the triangle <u>across</u> from the point/angle) is DF
- the hypotenuse (the<u> longest side</u> of the triangle) is EF.
sin ∠E = 
sin ∠E = 
(simplified)
The answer is 11 The answer is 11 The answer is 11
Answer:
a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:
b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence
Step-by-step explanation:
Answer:
1. H = 29 cm
2. θ = 44°
Step-by-step explanation:
1. We can find the height of the triangle by considering the isosceles triangle as two right triangles. The height can be found by using Pitagoras:
Where:
L: is the sides of the isosceles triangle = 42 cm
B: is the base = 30 cm
H: is the height =?
Then, the height is:
2. The two equal angles (θ) can be found using the following trigonometric identity:
Hence, the two equal angles are 44°.
I hope it helps you!
Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0
Discriminant = 4 - 4(K)(-1) = 4 + 4K
For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.
The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.
