Find the magnitude and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = -4i - 3j A. 5; 233.1° B.
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Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/
The upper limit => C.I_u = μ + Z*σ/
The lower limit => C.I_l = μ - Z*σ/
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/)
= 200 + (1.96*30)/
= 200 + 58.8/