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3 years ago

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Find the magnitude and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = -4i - 3j A. 5; 233.1° B.

7; 216.9° C. 5; 216.9° D. 5; 36.9°

1 answer:

Degger [83]3 years ago

4 0

Hello,

ρ=√(4²+3²)=5

tan θ=-3/-4=3/7

==>θ=216,869897...° (since θ is in the III quadrant)≈216.9°

Answer C

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