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2 years ago

7

you use a garden hose to fill a wading pool if the water level rise 12 centimeters every 5 minutes and you record the data point

of (15,y) what is the value of y

1 answer:

Shalnov [3]2 years ago

4 0

15/3= 5
so 5 x 12 = 60

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Due tomorrow Please help!!

anastassius [24]

Answer:

A

$\frac{1}{8}$ = $\frac{b}{4^{2} }$

b = $\frac{1}{8}$ × $4^{2}$

b = $\frac{4^{2} }{8}$

then b = $\frac{c^{2} }{a}$ that is ORANGE

B

-2 - v = -7

v = -7 +2

then v = k + m that is BROWN

C

$\frac{14}{q}$ = $\frac{-7}{-4}$

q = $\frac{14 * -4 }{-7}$

then q = $\frac{ps}{r}$ that is YELLOW

D

4m + 2(n) = 5 (n)

4m = 5 (n) - 2n

4m = 3n

m = $\frac{3n}{4}$

then m = $\frac{3n}{4}$ that is RED

E

-8 = $\frac{x}{-5}$ - 6

$\frac{x}{-5}$ = -8 + 6

x = -5 (-8 + 6)

then x = y( w + z ) that is LIGHT GREEN

7 0

3 years ago

Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a

andrew11 [14]

Answer:

Step-by-step explanation:

Given that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†).

a) $P(X\leq 15) = 0.1565=0.157$

b) $P(X>26) =1-F(26)\\= 1-0.9221\\=0.0779=0.078$

c) $P(15\leq x\leq 26)\\=F(26)-F(14)\\=0.9221-0.1049\\=0.8172=0.817$

d) 2 std dev = 2(20) =40

Hence 2 std deviation means

20-40, 20+40

i.e. (0,60)

$P(0$

5 0

3 years ago

(3x+14)° measurement in degrees a.20.00° b.40.25° c.42.50° d.74.00°

Marysya12 [62]

Answer:

B

Step-by-step explanation:

4 0

2 years ago

Can U pls Help Me pls

Mars2501 [29]

Answer:

angle x= 60

so it is in the ratio 1:2:√3

√3x=3

ie.x=√3/3

adjacent side=x=√3/4

8 0

3 years ago

Read 2 more answers

QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0

3 years ago