You figure out how long it would take a car traveling at 25 mph
to cover 360 ft. Any driver who does it in less time is speeding.
(25 mi/hr) · (5,280 ft/mile) · (1 hr / 3,600 sec)
= (25 · 5280 / 3600) ft/sec = (36 and 2/3) feet per second.
To cover 360 ft at 25 mph, it would take
360 ft / (36 and 2/3 ft/sec) = 9.82 seconds .
Anybody who covers the 360 feet in less than 9.82 seconds
is moving faster than 25 mph.
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If you're interested, here's how to do it in the other direction:
Let's say a car covers the 360 feet in ' S ' seconds.
What's the speed of the car ?
(360 ft / S sec) · (1 mile / 5280 feet) · (3600 sec/hour)
= (360 · 3600) / (S · 5280) mile/hour
= 245.5 / S miles per hour .
The teacher timed one car crossing both strips in 7.0 seconds.
How fast was that car traveling ?
245.5 / 7.0 = 35.1 miles per hour
Another teacher timed another car that took 9.82 seconds to cross
both strips. How fast was this car traveling ?
245.5 / 9.82 = 25 miles per hour
<span><span>(<span><span><span><span><span>4<span>x<span>−2</span></span></span><span>y^3</span></span>x</span></span><span>y<span>−4</span></span></span>)</span><span>−2</span></span><span>
=<span><span><span><span><span>x6</span><span>y^8/</span></span><span>16<span>y^6</span></span></span></span></span></span><span>
=<span><span><span><span>x^6</span><span>y^2/</span></span><span>16
Hope this helps:)
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Answer:
P = 12
Step-by-step explanation:
Given formula for the perimeter 'P' of a rectangle is,
P = 2L + 2W
If the values of L and W are,
L = 4 and W = 2
Perimeter of the rectangle = 2(L + W)
= 2(4 + 2)
= 2 × 6
= 12 units
Therefore, value of remaining variable 'Perimeter' = 12 units
(There is no use of 'pi' in calculating the perimeter of a rectangle).
There are two terms n2 and -5. n2 is the first term and -5 is the second term
Answer:
yes
Step-by-step explanation:
67.2 = 67.20 = 67.200 = 67.200...
