Answer:
16.93%.
Explanation:
- If we have 1.0 mol of Fe₃Al₂(SiO₄)₃:
∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = (no. of moles of Fe₃Al₂(SiO₄)₃)(the molecular mass of Fe₃Al₂(SiO₄)₃)
∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = (1)(the molecular mass of Fe₃Al₂(SiO₄)₃) = (the molecular mass of Fe₃Al₂(SiO₄)₃).
∴ The mass of 1.0 mol of Fe₃Al₂(SiO₄)₃ = 3(atomic weight of Fe) + 2(atomic weight of Al) + 3(molecular weight of (SiO₄)₃) = 497.7474 g.
The mass of Si in 1.0 mole of Fe₃Al₂(SiO₄)₃ = 3(atomic mass of Si) = 3(28.0855 g/mol) = 84.2565 g.
∵ The mass % of Si = (the mass of Si)/(the mass of Fe₃Al₂(SiO₄)₃) = (84.2565 g)/(497.7474 g) = 16.93%.
Answer : This is not an ideal mixture.
Explanation :
Using Raoult's law :
where,
= total vapor pressure of mixture
= vapor pressure of pure methanol = 256 torr
= vapor pressure of pure water = 55.3 torr
= mole fraction of water = 0.312
= mole fraction of methanol = 1 - 0.312 = 0.688
Now put all the given values in the above formula, we get:
From this we conclude that the total vapor pressure of mixture is less than the total given vapor pressure of 211 torr. That means, the interactions between the methanol and water would be weaker than those between the individual substances. So, this is not an ideal mixture.
Hence, this is not an ideal mixture.
A source region must have certain temperature and humidity properties that can remain fixed for a substantial length of time to affect air masses above it. above it. Air mass source regions occur only in the high or low latitudes; middle latitudes are too variable.
Answer:
he decided to become a teacher because he studied expertise and wanted to teach about early life
Explanation:
