Answer:
Explanation:
1. Find the empirical formula of a compound that has 36% of Calcium (Ca), 64% of Chlorine (Cl).
2. Find molar mass of each component: Ca=40.078, Cl=35.453
3 Convert to moles: Ca=0.8982484155896, Cl=1.8052068936338
4 Find smallest mole value: 0.8982484155896
5 Divide all components by the smallest value: Ca=1, Cl=2.0096967189738
6 Round to closest whole numbers: Ca=1, Cl=2
7 Combine to get the empirical formula: CaCl2
