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3 years ago

I need all those answers

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

5 0

Answer:

Step-by-step explanation:

4 :

A - 2 raised to the 5th power

______________________

2 raised to the 3 power

B: 5 raised to the 2nd power x 5 raised to the 3rd power

A: 4 raised to the 6 power

B: i forgot the rest

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Suppose that the cost (in dollars) for a company to produce x pairs of a new line of jeans is described by the formula below. C(

Ad libitum [116K]

Answer:

a) The marginal cost function is given by

C'(x) = 4 + 0.04x + 0.0003x² (in dollars)

b) C'(70) = $8.27

Step-by-step explanation:

C(x) = 1000 + 4x + 0.02x² + 0.0001x³

a) Marginal cost is usually defined as the cost of producing one extra unit of product. It expresses how much the total cost is changing with respect to number of units of product.

Mathematically,

MC = (dC/dx) = C'(x)

For this question,

C'(x) = 4 + 0.04x + 0.0003x²

b) C'(70) means the marginal cost at x = 70 units, that is, how much the total cost is changing after the production of 70 units; the cost of producing one extra unit of product after producing 70 units.

C'(x) = 4 + 0.04x + 0.0003x²

C'(70) = 4 + 0.04(70) + 0.0003(70²)

C'(70) = $8.27

Hope this helps!

8 0

3 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

$n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3$

The (1 - <em>α</em>)% confidence interval for the difference between two mean is:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }$

The critical value of <em>t</em> is:

$\alpha /2=0.05/2=0.025$

degrees of freedom $=n_{1}+n_{2}-2=200+200-2=398$

$t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96$

Compute the 95% confidence interval for the difference between two mean as follows:

$CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)$

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0

3 years ago

Please help it's due today!!!!!!

BlackZzzverrR [31]

Answer:

See Below

Step-by-step explanation:

We are given 3 equations.

3x + 8

5x - 20

and

5x + 4y

First lets solve for x using the first two

3x + 8 = 5x -20

Move the variables to one side

3x + 8 = 5x -20

-3x -3x

8 = 2x -20

+20 +20

28 =2x

28/2 =2x /2

14 = x

Now we have x = 14

Lets plug this into the second equation to solve for the angle

3(14) + 8

42 + 8 = 50

5(14) - 20

70 - 20 =50

Now, lets plug the x and the angle into the third equation to find y

5 (14) +4y = 50

70 + 4y = 50

-70 -70

4y = -20

4y/4 = -20/4

y = -5

So now we have:

x = 14

y = -5

and the angle = 50

Hope this helps!

6 0

3 years ago

a traffic survey showed that 1,048 cars passed through an intersection in one hour. which is the best estimate of how many cars

Nikitich [7]

8,384 cars will pass

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3 years ago

A gardener planted 5 rows of vegetables. Each row has 3 pepper plants and s squash plants. The garden contains a total of 20 pla

Natalija [7]

(5x3)(5xs)=20
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3 0

3 years ago