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Fofino [41]
3 years ago
7

I need all those answers

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer:

Step-by-step explanation:

4 :

A - 2 raised to the 5th power

    ______________________

      2 raised to the 3 power

B: 5 raised to the 2nd power  x  5 raised to the 3rd power

5:

A: 4 raised to the 6 power

B: i forgot the rest

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Oscar has a gift card with a $110 balance. He buys several video games that cost $15 each. After the purchases, his gift card ba
True [87]

Answer: Um... Not quite sure what you're asking, but he bought about 5 games with the gift card.

6 0
3 years ago
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Find the number of positive integers n is less than or equal to 1000 such that 15n is a perfect square.
boyakko [2]

Answer:

8 positive integers.

Step-by-step explanation:

One value of n would be 15 because 225 = 15^2.

Other values  are 225 * n where 15n  <= 1000 and n is a perfect square.

So n = 4 gives us 225* 4 = 900 which is a perfect square and 15*4 = 60.

n = 9  gives us 225 * 9 which is a perfect square and 15*9 = 135.

n = 16 gives us 225*16  and 15*16 = 240 , so OK.

n = 25   gives a perfect square and  and 15*25 = 375 - so OK.

n = 36 gives a perfect square and 15*36 = 540 - so OK.

n = 49 gives a perfect square and  15*49 = 735 - so OK.

n = 64 gives a perfect square and 15*64 = 960 - so ok.

n = 81 gives a perfect square and 15 * 81 = 1215  so NOT ok.

3 0
3 years ago
Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.
mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = ^{6}C_{1}\times^{4}C_{3}=6\times4=24

2 Boy and 2 girls=^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90

3 Boys and 1 girl = ^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80

4 Boys = ^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15

Now total number of ways = 24 + 90 + 80 + 15 = 209

7 0
3 years ago
(a) An angle measures 25°. What is the measure of its complement?
Setler79 [48]

Answer:

A) 65 degrees

B) 89 degrees

Step-by-step explanation:

Complementary angles always add up to 90 degrees whereas supplementary angles always add up to 180 degrees

Hope it helps :)

5 0
3 years ago
Pls someone help me or i’ll faint
never [62]
Answer:
a) DF = 20

b) DF =
Radical Form = sqrt(53)
Decimal Form = 7.28
5 0
3 years ago
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