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Elanso [62]
4 years ago
13

A store offers a 15% discount on a skirt. If Bernice pays $40.80 for the skirt, what was the list price of the skirt before the

discount? $61.00
Mathematics
2 answers:
liq [111]4 years ago
8 0

Answer: 48

Step-by-step explanation:

Did the test got it right

nadya68 [22]4 years ago
6 0
The answer to this question is: <span>x=48</span>
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Instructions: Find the missing side of the triangle.
Marrrta [24]

Answer:

100

Step-by-step explanation:

30 + 50 + x  = 180

80 + x = 180

x = 180 - 80

x = 100

5 0
2 years ago
Is 0.0575 greater than 5.75
Harrizon [31]

no. its not round it to 0 and 5 or 6

6 0
3 years ago
Read 2 more answers
. The temperature on Monday was −5∘C . By Tuesday the temperature rose to −2∘C. Find the change in temperature.
Alekssandra [29.7K]

Answer: 3^{\circ}C

Step-by-step explanation:

Given

The temperature on Monday was -5^{\circ}C

By Tuesday, it becomes -2^{\circ}C

Change in temperature is the difference between the two temperatures.

\Rightarrow \Delta T=-2-(-5)\\\Rightarrow \Delta T=-2+5\\\Rightarrow \Delta T=3^{\circ}C

Therefore, the change in temperature is 3^{\circ}C.

3 0
3 years ago
Express (8 - 3sqrt(2))/(4 + 3sqrt(2)) in the form of a + b * sqrt(2) where a and b are integers.​
Naya [18.7K]

Answer:   \boldsymbol{-25+18\sqrt{2}}

The expression is in the form a+b\sqrt{2} where a = -25 and b = 18

==========================================================

Work Shown:

Let x = 3\sqrt{2} and then square both sides

x = 3\sqrt{2}\\\\x^2 = \left(3\sqrt{2}\right)^2\\\\x^2 = \left(3\right)^2*\left(\sqrt{2}\right)^2\\\\x^2 = 9*2\\\\x^2 = 18\\\\

We'll use both x and x^2 later on.

---------------------

The denominator is in the form 4+x. We'll multiply top and bottom by 4-x to then use the difference of squares rule. This will allow us to eliminate the square root in the denominator.

\frac{8-3\sqrt{2}}{4+3\sqrt{2}}\\\\\frac{8-x}{4+x}\\\\\frac{(8-x)(4-x)}{(4+x)(4-x)}\\\\\frac{32-8x-4x+x^2}{16-x^2} \ \text{ difference of squares rule}\\\\\frac{32-12x+x^2}{16-x^2}\\\\

\frac{32-12*3\sqrt{2}+18}{16-18} \ \text{ plug in } x = 3\sqrt{2} \text{ and } x^2 = 18\\\\\frac{50-36\sqrt{2}}{-2}\\\\\frac{-2(-25+18\sqrt{2})}{-2}\\\\\boldsymbol{-25+18\sqrt{2}}

Therefore,

\frac{8-3\sqrt{2}}{4+3\sqrt{2}}=\boldsymbol{-25+18\sqrt{2}}

-------------------------------------

Checking the answer:

Use a calculator to find that,

\frac{8-3\sqrt{2}}{4+3\sqrt{2}} \approx 0.45584412271571 \\\\-25+18\sqrt{2} \approx 0.45584412271571

We get the same decimal approximation, which helps confirm the correct answer.

Or you could use the idea that if M = N, then M-N = 0 to subtract the original expression M and the final result N. You should get 0 or very close to it.

3 0
3 years ago
Kaya buys a $20 phone card. She is charged $.15 per minute for
marshall27 [118]
$1.50 because 0.15 x 10 is 1.50
4 0
3 years ago
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