1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olchik [2.2K]
3 years ago
11

Your solution should for this assignment should consist of five (5)files:============================================== FuelGaug

e.h (class specification file)FuelGauge.cpp (class implementation file)Odometer.h (class specification file)Odometer.cpp (class implementation file)200_assign6.cpp (application program)=================================================★ For your sixth programming assignment, you will be implementing a program that uses two(2)classes that work together to simulate a car’s fuel gauge and odometer. The classes you will design are: TheFuelGaugeClass: This class will simulate a fuel gauge. Its responsibilities are↘To know the car’s current amount of fuel, in gallons.↘To report the car’s current amount of fuel, in gallons.↘To be able to increment the amount of fuel by 1 gallon. This simulates putting fuel in the car. (The car can hold a maximum of 15 gallons)↘To be able to decrement the amount of fuel by 1 gallon, if the amount of fuel is greater than 0 gallons. This simulates burning fuel as the car runs.TheOdometerClass: This class will simulate the car’s odometer. Its responsibilities are:↘To know the car’s current mileage.↘To report the car’s current mileage.↘To be able to increment the current mileage by 1 mile. The maximum mileage the odometer can store is 999,999 miles. When this amount is execeeded, the odometer resets the current mileage to 0.↘To be able to work with aFuelGaugeobject. It should decrease theFuelGaugeobject’s current amount of fuel by 1 gallon for every 24 miles traveled. (The car’s fuel economy is 24 miles per gallon)The FuelGaugeclass should have at least one constructor, and the appropriate member functions to get the number of gallons, increment the number of gallons, and decrement the number of gallons.★ The odometer class should have at least one constructor, and the appropriate member functions to get the mileage and increment the mileage (unfortunately you cannot decrement the mileage!).★ In the odometer class, you can have a member variable that is a pointer to a FuelGauge object. This is how you can establish a relationship between the two classes that allow them to work together. For every mile the car is driven, the odometer is increased by 1, and for every 24 miles the car is driven, the number of gallons is reduced by one.★ So in the Odometer class, one of the private member variables should be of type fuel gauge* (pointer to a FuelGauge object).★ Demonstrate the two classes by creating instances(objects)of each. Simulate filling the car up with fuel, and then run a loop that increments the odometer until the car runs out of fuel. During each loop iteration, print the car’s current mileage and amount of fuel.
Computers and Technology
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer: provided in the explanation section

Explanation:

This was implemented in C++

Filename: Car.cpp

#include <iostream>

#include <iomanip>

#include <cstdlib>

#include "Odometer.h"

using namespace std;

int main()

{

  char response;

  do

  {

      FuelGuage* myFuel = new FuelGuage(6);

      int fuelLevel = myFuel->getFuel();

      cout << "Car gas level: " << fuelLevel << endl;

      cout << "Car is filling up" << endl;

      while(myFuel->getFuel() < 15)

      {

          myFuel->addFuel();

      }

      Odometer* car = new Odometer(myFuel, 999990);

      cout << "Car gas level: " << car->getFuelGuage()->getFuel() << endl;

      cout << "Car is off!" << endl;

      cout << "--------------------------" << endl;

      while(car->getFuelGuage()->getFuel() > 0)

      {

          car->addMile();

          int miles = car->getMileage();

          cout << "Mileage: " << setw(6) << miles << ", Fuel Level: " << car->getFuelGuage()->getFuel() << endl;

          cout<<"--------------------------------------------------------------"<<endl;

      }

      delete myFuel;

      delete car;

      cout << "Would you like to run the car again(Y/N)? ";

      cin >> response;

      system("cls||clear");

  } while(toupper(response) != 'N');

  return 0;

}

Filename: FuelGuage.cpp

#include "FuelGuage.h"

FuelGuage::FuelGuage()

{

  init();

}

FuelGuage::FuelGuage(int fuel)

{

  init();

  this->fuel = fuel;

}

FuelGuage::FuelGuage(const FuelGuage& copy)

{

  this->fuel = copy.fuel;

}

void FuelGuage::init()

{

  this->fuel = 0;

}

int FuelGuage::getFuel()

{

  return fuel;

}

void FuelGuage::addFuel()

{

  fuel++;

}

void FuelGuage::burnFuel()

{

  fuel--;

}

Filename:FuelGuage.h

#ifndef FUEL_GUAGE_H

#define FUEL_GUAGE_H

class FuelGuage

{

private:

  int fuel;

  void init();

public:

  FuelGuage();

  FuelGuage(int fuel);

  FuelGuage(const FuelGuage& copy);

  int getFuel();

  void addFuel();

  void burnFuel();

};

#endif

Filename : Odometer.cpp

#include "Odometer.h"

Odometer::Odometer()

{

  init();

}

Odometer::Odometer(FuelGuage* inFuel, int inMileage)

{

  init();

  this->fuel = new FuelGuage(*inFuel);

  this->mileage = inMileage;

  this->milesSinceAddingFuel = 0;

}

void Odometer::init()

{

  fuel = new FuelGuage();

  mileage = 0;

  milesSinceAddingFuel = 0;

}

FuelGuage* Odometer::getFuelGuage()

{

  return fuel;

}

int Odometer::getMileage()

{

  return mileage;

}

void Odometer::addMile()

{

  if(mileage < 999999)

  {

      mileage++;

      milesSinceAddingFuel++;

  }

  else

  {

      mileage = 0;

      milesSinceAddingFuel++;

  }

  if((milesSinceAddingFuel % 24) == 0)

  {

      fuel->burnFuel();

  }

}

void Odometer::resetMiles()

{

  milesSinceAddingFuel = 0;

}

Odometer::~Odometer()

{

  delete fuel;

}

Filename: Odometer.h

#ifndef ODOMETER_H

#define ODOMETER_H

#include "FuelGuage.h"

class Odometer

{

private:

  void init();

  int mileage;

  int milesSinceAddingFuel;

  FuelGuage* fuel;

public:

  Odometer();

  Odometer(FuelGuage* inFuel, int inMileage);

  FuelGuage* getFuelGuage();

  int getMileage();

  void addMile();

  void resetMiles();

  ~Odometer();

};

#endif

You might be interested in
What is the purpose of a system call in an operating system?
ikadub [295]

Answer:

 The system call is the programming way for executing the requesting the services in the program from kernel in the particular operating system.

The main purpose of the system call in the operating system is that it basically provide the different types of the services to the users by using the API (Application program interface) system.

It basically provide the interface for allowing the users to request the services between the operating system and a processor. In the linux there are basically three types of system call are as follows:

  • Fork
  • Waitpid
  • Exist

6 0
3 years ago
Software that allows users to use and adapt it for any purpose, often allowing the public to participate in further development
Sphinxa [80]

Answer:

Open Source

Explanation:

When a developer makes something open to the public, free to edit and use how they want, they make the project open source.

4 0
3 years ago
Read 2 more answers
assume an int array, candy, stores the number of candy bars sold by a group of children wherecandy[j] is the number of candy bar
GuDViN [60]

Answer:

The first one. Important notice sum should be equal to zero before calculating the total sum.

5 0
3 years ago
Read 2 more answers
Re:
aksik [14]

Answer:

A) create new records

B) open and close forms

C) open database forms

F) navigate through records

G) import and export data

Explanation:

5 0
3 years ago
. When attempting to minimize memory usage, the most efficient way to do group processing when using the MEANS procedure is to u
MrRissso [65]

Answer:

A. the BY statement.

Explanation:

The BY statement aids the procedure MEANS to develop the tree for the current BY group only, thereby analyze the stats, and clean the tree prior to the start and development of the next BY group.

However, without the BY statement, procedure MEANS develops its AVL tree for both the whole file and all sector estimates crossings established in CLASS.

Hence, in this case, the correct answer is the BY Statement.

8 0
3 years ago
Other questions:
  • In real-world environments, risks and their direct consequences will most likely span across several domains. However, in the la
    12·1 answer
  • What is a GUI?
    11·1 answer
  • The goal expressed in this definition states that data visualization is about ________________ .
    11·2 answers
  • Which of the following is a technique used by hackers to identify unsecured wireless network locations to other hackers?A. Blues
    10·1 answer
  • How I to turn this ''loop while'' in ''loop for''? var i = 0; while (i &lt; 20) { var lineY = 20 + (i * 20); line(0, lineY, 400,
    11·1 answer
  • Your windows system is used by several people, so you want increase security by requiring users to create passwords that are at
    9·1 answer
  • When you expect a reader of your message to be uninterested, unwilling, displeased, or hostile, you should Group of answer choic
    15·1 answer
  • Which one you choosing? PS5 OR THE XBOX SERIES X???
    14·2 answers
  • When can designers use rapid application development?
    8·1 answer
  • Debugging 2.17.3: Debug: The Two Towers Code Hs
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!