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AnnyKZ [126]
3 years ago
5

Fill in the blank. A ___ is a substance that cannot be separated into simpler substances by physical or mechanical methods such

as filtering, boiling, or sifting
Chemistry
2 answers:
Ganezh [65]3 years ago
8 0
An element cannot be broken down any further. Elements can be found on the periodic table

PolarNik [594]3 years ago
8 0
I think it's a pure substance 
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Why is the use of high-frequency radio waves a beneficial technological advancement
Lynna [10]

Answer:

I think It's C

Explanation:

due to higher waves can get easy transfers and receive those signals for most things, such as radios, TVs, phone signals etc etc

4 0
2 years ago
Indicate the charge carried by the following atomic particles:
Dovator [93]
Answer:
A. Protons are positive and carry a charge of +1
B. Neutrons are neutral so carry a charge of 0
C. Electrons are negative and carry a charge of -1
5 0
2 years ago
Read 2 more answers
Select the correct answer. Elements Electronegativity aluminum (Al) 1.61 calcium (Ca) 1 carbon (C) 2.55 chlorine (Cl) 3.16 fluor
marishachu [46]

Answer: Fe - O


Explanation:


1) Start by showing the chart information in a more understandable way:


Elements ---------- Electronegativity


aluminum (Al) ----- 1.61


calcium (Ca) ------- 1


carbon (C) ---------- 2.55


chlorine (Cl) -------- 3.16


fluorine (F) --------- 4


hydrogen (H) ------ 2.2


iron (Fe) ------------- 1.83


nitrogen (N) --------- 3.04


oxygen (O) ----------- 3.44


phosphorus (P) ----- 2.19


potassium (K) -------- 0.82


silicon (Si) ------------- 1.9


sulfur (S) --------------- 2.58


2) Find the electronegativity differences for the atoms in each compound:


i) Ca – Cl: 3.16 - 1 = 2.16


ii) Fe – O: 3.44 - 1.83 = 1.61


iii) H – S: 2.58 - 2.2 = 0.38


iii= F – F = 4 - 4 = 0


3) Analysis


i) The higher the electronegativity difference between two non-metal elements, the the more the polar the covalent bond. Therefore, the bond H - S is the most polar among the non-metal - non-metal bonds listed. But 0.38 is a small difference, so this is not very polar.


ii) For metal - non-metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and so you cannot classify the bond as polar but as ionic. Therefore, Ca - Cl with 2.16 electronegativity difference is a ionic bond.


iii) The bond in Fe – O has electronegativty difference of 1.61, so it is yet covalent, and highly polar.


Read more on Brainly.com - brainly.com/question/1309389#readmore


<h3>~*"AUBA14"*~</h3>
8 0
3 years ago
Read 2 more answers
5.1169 mol of Ne is held at 0.9148 atm and 911 K. What is the volume of its container in liters?
sveticcg [70]

By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres

<h3>Boyle's  Law</h3>

Given Data

  • number of moles of Ne = 5.1169 mol
  • Pressure = 0.9148 atm
  • Temperature = 911 K

We know that the relationship between pressure and temperature is given as

PV = nRT

R = 0.08206

Making the volume subject of formula we have

V= nRT/P

Substituting our given data to find the volume we have

V = 5.1169*0.08206*911/0.9148

V = 382.522353554/0.9148

V = 418.14 L

Learn more about Boyle's law here:

brainly.com/question/469270

5 0
2 years ago
A sample of 9.00 grams of aluminum metal is added to an excess of hydrochloric acid. The volume of hydrogen gas produced at stan
marysya [2.9K]

Answer:

The volumen of hydrogen (H) is 11.22 L

Explanation:

The balanced reaction between the aluminum (Al) and the hydrochloric acid (HCl) is:

2Al(s) + 6HCl(l) --> 2AlCl3(ac) + 3H2(g)

It is a reduction-oxidation reaction.

At the beginning we have 9.00 grams of Al what represents an certain amount of moles. Then, we know the molar mass of Al is 26.9815 g/mol, so the moles content in 9.00 g of Al are :

9.00 g Al * (1 mol Al / 26.9815 g Al)= 0.33356 mol Al

Now, we have to conisdered the molar relation between the Al and H2, according to the balanced reaction performed above. That is 2:3 (Al:H2)

Then,

0.33356 mol Al * (3 mol H2/  2mol Al) = 0.50034 mol H2

In this point, we can considered the H2 like a noble gas, because the question ask for standard temperature and pressure (0° C= 273.15K and 1 atm).

Let us remember the noble gases equation

PV=nRT

P: pressure

V: Volumen

n: number of moles

R: gases constant

T: temperature

For the volumen, the equation is:

V= (nRT/P)

Now: V= (0.50034 mol * 0.0821 (L*atm/K*mol) * 273.15 K)/ (1 atm)

         V= 11.22 L

3 0
3 years ago
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