<u>Answer:</u> The volume of concentrated solution required is 42 mL
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated solution
are the molarity and volume of diluted solution
We are given:
Putting values in above equation, we get:
Hence, the volume of concentrated solution required is 42 mL
Answer:
0.03697 mol Al₂(SO₄)₃
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Explanation:
<u>Step 1: Define</u>
12.65 g Al₂(SO₄)₃
<u>Step 2: Identify Conversions</u>
Molar Mass of Al - 26.98 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol
<u>Step 3: Convert</u>
<u /> = 0.03697 mol Al₂(SO₄)₃
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
We already have 4 sig figs in the final answer, so no need to round.