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shtirl [24]
3 years ago
7

I need help with 1-10 , thanks!

Mathematics
2 answers:
LiRa [457]3 years ago
7 0

You don't need help; those look right.  Write them as a fraction as requested, so the first is

Q1    \qquad \dfrac{35}{5} = \dfrac{7}{1}

Q2     \quad\dfrac{35}{11}

No reducing required on that one.

Q3     \quad\dfrac{35}{7}=\dfrac{5}{1}

Q4     \quad\dfrac{5}{35}=\dfrac{1}{7}

Q5     \quad\dfrac{5}{7}

I'll leave the rest.

swat323 years ago
7 0
You already have some done, and they all are correct. We can finish the ones that you havven't completed.
Q1: Your answer is correct.
Q2:11 is a prime number, so it can't get divided and have a whole number (other by itself and one). So, the answer is \frac{35}{11} or 3 \frac{2}{11}
Q3:Your answer is correct.
Q4: Your answer is correct.
Q5:5 and 7 are prime numbers. So, the answer is \frac{5}{7}
Q6:11 is a prime number. So, the answer is \frac{11}{35}
Q7: 11 and 7 are prime numbers. So, the answer is \frac{11}{7} or 1  \frac{4}{7}
Q8: 35 can be divided by 7 5 times. So, the answer is \frac{1}{5}
Q9:7 and 5 are prime numbers. So, the answer is \frac{7}{5} or 1  \frac{2}{5}
Q10: 7 and 11 are prime numbers. So, the answer is \frac{7}{11}

Hope this helps!!
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Answer:

Step-by-step explanation:

1) Reagrupar términos.

3(5x + 1) = 15x^3

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5x + 1 = 5x^3

3) Mueva todos los términos a un lado.

5x + 1 - 5x^3 = 0

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2 years ago
Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
bagirrra123 [75]

Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

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3 years ago
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loris [4]

Answer:

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