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3 years ago

Determine whether the following graph represents a function.

Mathematics

1 answer:

4vir4ik [10]3 years ago

8 0

Answer:

function

Step-by-step explanation:

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There are two formulas that can be used to find the volume of a rectangular prism. Find the volume using both formulas.

Rina8888 [55]

Answer:

Volume = $\frac{1}{8}$ cubic units.

Step-by-step explanation:

The volume of a rectangular prism is given by,

$V = (\textrm {Length}) \times (\textrm {Width}) \times (\textrm {Height})$ .......... (1) and

$V = (\textrm {Base Area})\times (\textrm {Height})$ .......... (2)

Now, the length of the given prism is $\frac{1}{2}$ units, width is $\frac{1}{2}$ units and the height is $\frac{1}{2}$ units.

So. from equation (1) the volume, V = $(\frac{1}{2}) \times (\frac{1}{2}) \times (\frac{1}{2}) = \frac{1}{8}$ cubic units.

Now, base area = B = $(\frac{1}{2}) \times (\frac{1}{2}) = \frac{1}{4}$ sq. units.

So, from equation (2) we get

$V = (\frac{1}{4}) \times (\frac{1}{2}) = \frac{1}{8}$ cubic units. (Answer)

4 0

3 years ago

Geometry question to verify it

Oksana_A [137]

Step-by-step explanation:

here's the solution,

in the given figure , sum of all angles formed with O measures 360°

because, it forms a complete angle

so,

=》mPOQ + mQOR + mROS + mSOT + mTOP = 360°

=》mPOQ + mQOR + mROS + mSOT + mTOP = (90° × 4)

=》mPOQ + mQOR + mROS + mSOT + mTOP = 4 × right angle

(cuz.. right angle = 90°)

4 0

3 years ago

Solve this equation pls

Aleksandr-060686 [28]

Answer:

${ \rm{y = \frac{3 \sqrt{x} + 2x}{ {4x}^{2} } }} \\$

• We are gonna use the quotient rule

${ \boxed{ \bf{ \frac{dy}{dx} = \frac{ {\huge{v} } \frac{du}{dx} - { \huge{u}} \frac{dv}{dx} }{ {v}^{2} } }}} \\$

u is (3√x + 2x)
v is 4x²
du/dx is 3/2√x
dv/dx is 8x

• Therefore:

${ \rm{ \frac{dy}{dx} = \frac{(4 {x}^{2})( \frac{3}{2 \sqrt{x} }) - (3 \sqrt{x} + 2x)(8x) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{(6 {x}^{2})( {x}^{ - \frac{1}{2} } ) - (24 {x}^{ \frac{3}{2} } + 16 {x}^{2} ) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ 6 {x}^{ \frac{3}{2} } - {24x}^{ \frac{3}{2} } - {16x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ - 18 {x}^{ \frac{3}{2} } - 16 {x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = - 2 {x}^{ \frac{3}{2} } (9 + 8 {x}^{ \frac{4}{3} } ) \div 16 {x}^{4} }} \\ \\ { \boxed{ \boxed{ \rm{ \: \: \frac{dy}{dx} = - \frac{8 \sqrt{ {x}^{ \frac{8}{3} }} + 9}{8x {}^{ \frac{8}{3} } } \: \: }}}}$