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Arturiano [62]
3 years ago
5

4x - Зу = -3 4x + y = 17 Explain how as well

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Step-by-step explanation:

I will solve your system by substitution.

(You can also solve this system by elimination.)

4x+y=17;4x−3y=−3

Step: Solve4x+y=17for y:

4x+y+−4x=17+−4x(Add -4x to both sides)

y=−4x+17

Step: Substitute−4x+17foryin4x−3y=−3:

4x−3y=−3

4x−3(−4x+17)=−3

16x−51=−3(Simplify both sides of the equation)

16x−51+51=−3+51(Add 51 to both sides)

16x=48

16/x = 48/16

(Divide both sides by 16)

x=3

Step: Substitute 3 for x in y=−4x+17:

y=−4x+17

y=(−4)(3)+17

y=5(Simplify both sides of the equation)

Answer:

x=3 and y=5

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The output of a function is 5 more than 2 times the input. Find the input when the output is 17.
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Answer:

<em>The input when the output is 17 is x=6.</em>

Step-by-step explanation:

<u>Functions</u>

Assume the input is called x and the output is the function f(x). Two times the input is 2x. 5 more than that is 2x+5.

Knowing the output of the function is 5 more than 2 times the input, we can write the function as:

f(x)=2x+5

Now find the input x when the output is 17:

17=2x+5

Swap sides of the equation:

2x+5=17

Subtract 5:

2x=17-5=12

Divide by 2:

x=12/6=6

The input when the output is 17 is x=6.

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Well, to see if she can afford the skateboard, start by finding the discount and then finding the sales tax of that.

To find the discount, first find 15% of $139.99 and then subtract it since that's how much you're getting off.

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15% ÷ 100 = 0.15

$139.99 x 0.15 = 20.9985, which can be rounded up to $21.

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Now that we have the discount, we find the sales tax, which can be found the same way as the discount, but we add it to the total instead fo subtracting it.

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<em>This is the final total of how much the skateboard would cost.</em>

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No, she would not have enough money to buy the skateboard. With the discount alone, she could afford it, since $118 falls in her budget range, but with the added tax, it's 13 dollars over and she cannot afford the skateboard.

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