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jasenka [17]
3 years ago
10

1)Which conditions will result in the smallest change in momentum?. A)a large force over a long time period. B)a large force ove

r a short time period. c)a small force over a long time period. D)a small force over a short time period. 2)When comparing the momentum of two moving objects, which of the following is correct?. A)The object with the higher velocity will have less momentum if the masses are equal.. B)The more massive object will have less momentum if its velocity is greater.. C)The less massive object will have less momentum if the velocities are the same.. The more massive.
Physics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0
1. "A small force over a short time period" is the condition that <span>will result in the smallest change in momentum. The correct option among all the options that are given in the question is the last option or option "D".

2. "</span>The less massive object will have less momentum if the velocities are the same" is the correct choice among the following. <span>The correct option among all the options that are given in the question is the third option or option "C".</span>
fiasKO [112]3 years ago
3 0
D, small force for short time, as it has the least influence on the velocity. 
C, momentum is velocity x mass, so if velocities are the same, then the object with less mass with have a lower momentum.
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Explanation:

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2 years ago
A cable that weighs 8 lb/ft is used to lift 900 lb of coal up a mine shaft 650 ft deep. Find the work done. Show how to approxim
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Answer:

2275000 lb.ft

Explanation:

Let work done on the cable be denoted by: W_ca

Let work done on the coal be denoted by: W_co

Now, dividing the cable into segments, let x represent the length from top of the mine shaft to the segment.

Meanwhile let δx be the length of the segment.

We are told the cable weighs 8 lb/ft. Thus;

Work done on one segment = 8 × δx × x = 8x•δx

Therefore, work done on cable is;

W_ca = ∫8x•δx between the boundaries of 0 and 650

Thus;

W_ca = 4x² between the boundaries of 0 and 650

W_ca = 4(650²) - 4(0²)

W_ca = 1,690,000 lb.ft

Workdone on the 900 lb of coal will be calculated as;

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Total work done = W_ca + W_co

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6 0
3 years ago
This questic concerns a tablet that
Vanyuwa [196]

Answer:

The remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

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N(t)=N_0\,e^{-k\,\,t}

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This in percent form is 88.7 %. That is, the remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

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3 years ago
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s344n2d4d5 [400]
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4 years ago
Economics is the study of producing and ____ goods and services.
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hope this helps

3 0
4 years ago
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