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3 years ago

I'LL GIVE ONE OF YOU BRAINLIEST ANSWER. PLEASE HELP ME

Physics

1 answer:

True [87]3 years ago

8 0

A) The magnitude of the electric field = (electric force)/(charge of particle)

Electric force = (charge of particle) (electric field magnitude)
= (2 C)(2.35 N/C) = 4.7 N

(electric force and electric field are always in the same direction)
so, force = 4.7 N south

b) Electric field magnitude = (electric force)/(particle charge)
= (6*10^-3 N)/(-4 C) = -0.0015 N/C = -1.5*10^-3 N/C east

For part d, I think I'll need to see part c first.

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3 years ago

A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.

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Answer:

Velocity= 19.05 m/s

Kinetic energy= 3.08 J

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The corn possess potential energy. Feom law of conservation of energy, all the potential eneegy will be converted to kinetic energy, with negligible friction.

Potential energy, PE= kinetic energy, KE

Potential energy is given by mgh while kinetic energy is given by $0.5mv^{2}$

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$mgh=0.5mv^{2}$

Making v the subject of the formula then

$v=\sqrt {2gh}$

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$v=\sqrt {2\times 9.81\times 18.5}=19.0517715711689\ m/s\\v\approx 19.05\ m/s$

To get the kinetic eneegy, since PE=KE AND KE is

$KE=0.5mv^{2}$

Substituting v with 19.05 and m with 0.017 kg we have

$0.5\times 0.017\times 19.05^{2}=3.08467125/ J\approx 3.08 J$

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