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3 years ago

A roller coaster is moving 10 m/s and a mass of 7 kg. The roller coaster has

Physics

1 answer:

Arada [10]3 years ago

3 0

<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

A roller coaster is moving 10 m/s and a mass of 7 kg. The roller coaster has kinetic energy.

Ek = 1/2 x 7 x 10²
Ek = 350 J

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What is the answer for this please

RoseWind [281]

Answer:

NEil bohr

Explanation:

option number 1

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3 years ago

A disk-shaped grindstone of mass 1.7 kg and radius 8 cm is spinning at 730 rev/min. After the power is shut off, a woman continu

Anastasy [175]

Answer:

0.186 N-m

Explanation:

mass of the grindstone, $m=1.7 kg$

radius, $r=8 cm$

Frequency, $f=730 rev/min = 12.16 rev/s$

time, $t=9s$

final angular velocity, $\omega=0$

Initial angular velocity,

$\omega_o=2\pi f\\=2\pi (12.16) rad/s\\= 76.36 rad/s$

Angular acceleration of the grind stone is:

$\alpha=\frac{\omega-\omega_o}{t}\\\Rightarrow \alpha =\frac{0-76.36}{9} = -8.48 rad/s^2$

Moment of inertia:

$I=mr^2+mr^2=2mr^2$

$I=2\times 1.7 kg\times (0.08m)^2= 0.022kg-m^2$

Torque exerted by the ax on the grind stone is:

$\tau=I\alpha\\\tau=0.022\times (-8.48) \\\tau=0.186N-m$

8 0

4 years ago

A wheel rotates about a fixed axis with a constant angular acceleration of 4.0 rad/s2. The diameter of the wheel is 40 cm. What

Ray Of Light [21]

Answer:

v = 0.42m/s

Explanation:

In order o calculate the linear speed of the point at the border of the wheel, you first take into account that the total acceleration of such a point is given by:

$a_{total}^2=a_r^2+a_t^2$ (1)

atotal: total acceleration = 1.2m/s^2

ar: radial acceleration of the wheel

at: tangential acceleration

The tangential acceleration is also given by:

$a_t=r\alpha$ (2)

r: radius of the wheel = (40cm/2 )= 20cm = 0.2m

α: angular acceleration = 4.0rad/s^2

You replace the expression (2) into the expression (1) and solve for the radial acceleration:

$a_{total}^2=a_r^2+(r\alpha)^2\\\\a_r=\sqrt{(a_{total})^2-(r\alpha)^2}\\\\a_r=\sqrt{(1.2m/s^2)^2-((0.2m)(4.0rad/s^2))^2}=0.894\frac{m}{s^2}$

Next, you use the following formula for the radial acceleration and solve for the linear speed:

$a_r=\frac{v^2}{r}\\\\v=\sqrt{ra_r}=\sqrt{(0.2m)(0.894m/s^2)}=0.42\frac{m}{s}$

The linear speed of the point at the border of the wheel is 0.42m/s

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3 years ago

A subtence floats or sinks in onother becauseof its relitivity

Helga [31]

No. A substance floats or sinks in another substance because of
the densities of both of them.

If the density of the substance is more than the density of the other
one, it will sink. If less than the density of the other one, it will float.

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4 years ago

Because communication involves two or more people acting in both sender and receiver roles and because their messages are depend

djyliett [7]

Answer:

Transactional process

Explanation:

Because communication involves two or more people acting in both sender and receiver roles and because their messages are dependent on and influenced by those of their partner means that communication is a transactional process i.e. a give and take process.

If the sender relays a message and the receiver does not reply or reply not taking cognizance of the sender's message, communication has not taken place.

For example, if consider this.

Sender: How old are you?

Reciever: My Cat is Red.

The response of the receiver is not in tune with the sender and so communication has not taken place.

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3 years ago