The easiest way is to fill two very light globes, each with a different gas.
Blow globe 1 with gas from the cylinder marked with label 1, and blow glove 2 with gas from the cylinder marked with label 2.
If a globe ascends in the air, it is because its gas is less dense than air.
Inflate the globes quite enough to be sure that the mass of the rubber of the globe is not important relative to the mass of gas and so it does not change the results. If you obtain a result where the globe does not have a cliea ascending or descending motion, you can inflate more the globe and it shouuld start to rise if the gas really is less dense than air.
I believe the answer is stored energy.
Nuclear reaction you are literally splitting an atom and in a chemical reaction you are not
Answer:
The options are not shown, so let's derive the relationship.
For an object that is at a height H above the ground, and is not moving, the potential energy will be:
U = m*g*H
where m is the mass of the object, and g is the gravitational acceleration.
Now, the kinetic energy of an object can be written as:
K = (1/2)*m*v^2
where v is the velocity.
Now, when we drop the object, the potential energy begins to transform into kinetic energy, and by the conservation of the energy, by the moment that H is equal to zero (So the potential energy is zero) all the initial potential energy must now be converted into kinetic energy.
Uinitial = Kfinal.
m*g*H = (1/2)*m*v^2
v^2 = 2*g*H
v = √(2*g*H)
So we expressed the final velocity (the velocity at which the object impacts the ground) in terms of the height, H.
