Answer:
x=-3
Step-by-step explanation:
4/x=8/(x-3)
We can solve this using cross products
4 ( x-3) = 8x
Distribute
4x -12 = 8x
Subtract 4x from each side
4x-4x-12 = 8x-12-4x
-12 =4x
Divide each side by 4
-12/4 = 4x/4
-3 =x
Answer:
n = 15
Step-by-step explanation:
6(1+n)=8n-3(n-7)
Distribute
6 +6n = 8n -3n +21
Combine like terms
6+6n = 5n +21
Subtract 5n from each side
6+6n-5n = 5n-5n +21
6 +n = 21
Subtract 6 from each side
6-6+n = 21-6
n = 15
Answer:
AC = 2.44
Step-by-step explanation:
Reference angle = 26°
Opposite side = AC = ?
Adjacent side = BC = 5
Applying TOA, we have:
Tan 26 = opp/adj
Tan 26 = AC/5
multiply both sides by 5
Tan 26 × 5 = AC
AC = 2.44 (nearest hundredth)
Answer:
Step-by-step explanation:
x8x8=201.06192983square inches
(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
