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Lady bird [3.3K]
3 years ago
13

How to do Simplification of algebraic fractions

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0
If we want to simplify Algebraic Fractions:
We have to take a look at the numerator and the denominator
Why? Because to simplify we need to have a common multiple.
When we find the common multiple, we now know by which factor we have to break down the fraction in the numerator and the denominator
I have some examples attached below for help.

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Answer:

View explanation.

Step-by-step explanation:

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Images from https://www.creditcardinsider.com/blog/happens-credit-card-bill-make-return/

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3 years ago
The interest rate r required to increase your investment p to the amount a in t years is found by mc075-1.jpg. Find the interest
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I hope this is the answer :)
45.67=r

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3 years ago
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A bicyclist rides the same number of miles every minute. The ratio table below shows the number of miles she rides during certai
nika2105 [10]

Answer:

B) Find the ratio of minutes to miles, 4:1. Multiply 7.5 by 4

Step-by-step explanation:

A bicyclist rides the same number of miles every minute. The ratio table below shows the number of miles she rides during certain amounts of time.

Biking Times and Distances        

Number of Minutes         Number of Miles

10                                             2.5

16                                              4

?                                              7.5

48                                              12

Which statement explains how to find the number of minutes it takes to bike 7.5 miles?

B) Find the ratio of minutes to miles, 4:1. Multiply 7.5 by 4....

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3 years ago
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Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

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3 years ago
Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6. The probability that the sum of the numbers rolled
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<span>Two dice (each die has 6 sides) can be combined to form 36 different possibilities (6 x 6). 
</span>
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