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3 years ago

What does 58/6 equal

Mathematics

1 answer:

Katen [24]3 years ago

5 0

Answer:

9.66666666667

Step-by-step explanation:

The fraction 58

is equivalent to 9 2

This fraction is a improper fraction once the absolute value of the top number or numerator (58) is greater than the absolute value of the bottom number or denomintor (6). So, the equivalent fraction is a mixed number which is made up of a whole number (9) and a proper fraction (2

The fraction 58

is equal to 58÷6 and can also be expressed as a decimal as 9.66667 and expressed as a percentage as 966.7%.

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If a 12-meter-tall airplane hangar casts a 18-meter shadow at the same time a parked jet casts a 6-meter shadow , how tall is th

8090 [49]

Given
12 meters tall airplane
18 meter shadow of airplane
6 meter shadow of jet
Find the measurement of the jet (y)
Solution
6y = 12 + 18 30
----- --------- ----> y = ------- -----------> y= 5
6 6 6

The answer is 5 meters tall is the measurement of a parked jet.

5 0

4 years ago

Add: 7,288 + 6,627 + 4,515

PIT_PIT [208]

18,430! I hope this helps you out!

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3 years ago

A cylinder shaped can needs to be constructed to hold 500 cubic centimeters of soup. The material for the sides of the can costs

iogann1982 [59]

Answer:

r=3.628cm

h=12.093cm

Step-by-step explanation:

For this problem we are going to use principles, concepts and calculations from multivariable calculus; mainly we are going to use the Lagrange multipliers method. This method is thought to help us to find a extreme value of a multivariable function 'F' given a restriction 'G'. F represents the function that we want to optimize and G is just a relation between the variables of which F depends. The Lagrange method for just one restriction is:

$\nabla F=\lambda \nabla G$

First, let's build the function that we want to optimize, that is the cost. The cost is a function that must sum the cost of the sides material and the cost of the top and bottom material. The cost of the sides material is the unitary cost (0.03) multiplied by the sides area, which is $A_s=2\pi rh$ for a cylinder; while the cost of the top and bottom material is the unitary cost (0.05) multiplied by the area of this faces, which is $A_{TyB}=2\pi r^2$ for a cylinder.

So, the cost function 'C' is:

$C=2\pi rh*0.03+2\pi r^2*0.05\\C=0.06\pi rh+0.1\pi r^2$

The restriction is the volume, which has to be of 500 cubic centimeters:

$V=500=\pi r^2h\\500=\pi hr^2$

So, let's apply the Lagrange multiplier method:

$\nabla C=\lambda \nabla V\\\frac{\partial C}{\partial r}=0.06\pi h+0.2\pi r\\\frac{\partial C}{\partial h}=0.06\pi r\\\frac{\partial V}{\partial r}=2\pi rh\\\frac{\partial V}{\partial h}=\pi r^2\\(0.06\pi h+0.2\pi r,0.06\pi r)=\lambda (2\pi rh,\pi r^2)$

At this point we have a three variable (h,r, λ)-three equation system, which solution will be the optimum point for the cost (the minimum). Let's write the system:

$0.06\pi h+0.2\pi r=2\lambda \pi rh\\0.06\pi r=\lambda \pi r^2\\500=\pi hr^2$

(In this kind of problems always the additional equation is the restricion, in this case, V=500).

Let's divide the first and second equations by π:

$0.06h+0.2r=2\lambda rh\\0.06r=\lambda r^2\\500=\pi hr^2$

Isolate λ from the second equation:

$\lambda =\frac{0.06}{r}$

Isolate h from the third equation:

$h=\frac{500}{\pi r^2}$

And then, replace λ and h in the first equation:

$0.06*\frac{500}{\pi r^2} +0.2r=2*(\frac{0.06}{r})r\frac{500}{\pi r^2} \\\frac{30}{\pi r^2}+0.2r= \frac{60}{\pi r^2}$

Multiply all the resultant equation by $\pi r^{2}$ :

$30+0.2\pi r^3=60\\0.2\pi r^3=30\\r^3=\frac{30}{0.2\pi } =\frac{150}{\pi}\\r=\sqrt[3]{\frac{150}{\pi}}\approx 3.628cm$

Then, find h by the equation $h=\frac{500}{\pi r^2}$ founded above:

$h=\frac{500}{\pi r^2}\\h=\frac{500}{\pi (3.628)^2}=12.093cm$

4 0

3 years ago

PLEASE HELP ASAP<br><br> What is the missing statement for the sixth step in the proof below?

alexira [117]

Answer:

Step-by-step explanation:

The last reasoning is the side angle side theorem. In the whole proof, there is no mention of an angle. So the answer has to involve prooving that the angle in between the two sides that have been proven similar is the same in both traingles. This is best accomplished by statement C.

4 0

2 years ago

A machine operation produces bearings whose diameters are normally distributed, with a mean of 0.497 inch and a standard deviati

eduard

Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.

That is;
P(x<0.496) and P(x>0.504) are not acceptable.

Now,
P(x<0.496) = P(Z< (0.496-0.497)/0.003)) = P(Z<-0.33)
From Z tables, P(Z<-0.33) = 0.3707

Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099

Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%

6 0

3 years ago