4 years ago

I need to solve for x

1 answer:

4 0

$BE=BD+DE=BC+CE\\\\BD=19,\ DE=5,\ BC=x+13,\ CE=x+15\\\\\text{substitute}\\\\19+5=(x+13)+(x+15)\\\\24=x+13+x+15\\\\24=2x+28\qquad|-28\\\\-4=2x\qquad|:2\\\\-2=x\to x=-2\\\\Answer:\ C)\ -2$

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