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Dmitry_Shevchenko [17]
2 years ago
5

What's 2,000 times 4,000???

Mathematics
2 answers:
Gennadij [26K]2 years ago
8 0

Answer:

8,000,000

Step-by-step explanation:

all you have to do is multiply the 4*2 then add the missing 0's for example so its 8 then add the six zeros behind the 8

AnnyKZ [126]2 years ago
7 0

Answer:

8000000

Step-by-step explanation:

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Calculus graph please help
tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of <em>y</em> = f'(x) and we want to determine the characteristics of f(x).

Part A)

<em>f</em> is increasing whenever <em>f'</em> is positive and decreasing whenever <em>f'</em> is negative.

Hence, <em>f</em> is increasing for the interval:

(-\infty, -2) \cup (-1, 1)\cup (3, \infty)

And <em>f</em> is decreasing for the interval:

\displaystyle (-2, -1) \cup (1, 3)

Part B)

<em>f</em> has a relative maximum at <em>x</em> = <em>c</em> if <em>f'</em> turns from positive to negative at <em>c</em> and a relative minimum if <em>f'</em> turns from negative to positive to negative at <em>c</em>.

<em>f'</em> turns from positive to negative at <em>x</em> = -2 and <em>x</em> = 1.

And <em>f'</em> turns from negative to positive at <em>x</em> = -1 and <em>x</em> = 3.

Hence, <em>f</em> has relative maximums at <em>x</em> = -2 and <em>x</em> = 1, and relative minimums at <em>x</em> = -1 and <em>x</em> = 3.

Part C)

<em>f</em> is concave up whenever <em>f''</em> is positive and concave down whenever <em>f''</em> is negative.

In other words, <em>f</em> is concave up whenever <em>f'</em> is increasing and concave down whenever <em>f'</em> is decreasing.

Hence, <em>f</em> is concave up for the interval (rounded to the nearest tenths):

\displaystyle (-1.5 , 0) \cup (2.2, \infty)

And concave down for the interval:

\displaystyle (-\infty, -1.5) \cup (0, 2.2)

Part D)

Points of inflections are where the concavity changes: that is, <em>f''</em> changes from either positive to negative or negative to positive.

In other words, <em>f </em>has an inflection point wherever <em>f'</em> has an extremum point.

<em>f'</em> has extrema at (approximately) <em>x</em> = -1.5, 0, and 2.2.

Hence, <em>f</em> has inflection points at <em>x</em> = -1.5, 0, and 2.2.

7 0
2 years ago
GIVING BRAINLIEST TO PERSON AHO ANSWERS FIRST!!
zavuch27 [327]
Please refer to the photograph attached for the answer
Hope you find the answers correct
Sorry you will find it really small please zoom in to see the answer to this question
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4 0
2 years ago
Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

a\cdot b=0

By using the property

(u+v)\cdot (u-v)=0

We know that

(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2

\mid u\mid ^2-\mid v\mid^2=0

\mid u\mid^2=\mid v\mid^2

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

\mid u\mid=\mid v\mid

Hence, the length of vectors u and v must have the same length.

5 0
3 years ago
Jermiah makes a recipe that calls for 1 1/2 cups of flour and 3/4 stick of butter. If Jermiah uses 3 sticks of butter, how many
xz_007 [3.2K]

Answer:

The answer is 6 cups of flour.

7 0
3 years ago
what is consecutive whole numbers? I have to write an algebraic expression for the sum of three consecutive whole numbers... :(
Agata [3.3K]

Answer:

Consecutive whole numbers (or integers) are numbers that directly follow one another.

Eg: 1, 2, 3, 4, 5 are consecutive whole numbers.

Step-by-step explanation:

Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108.

or

let the three consecutive whole numbers is x, x+1,and x+2

x + x+1 + x+2 = 4+2(x+1)

3x+3=4+2x+2

3x-2x=6-3

x=3

the other two numbers are 3+1=4,and 3+2=5

so the three numbers are 3,4 and 5

7 0
3 years ago
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