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dedylja [7]
3 years ago
5

Find the level of a two-sided confidence interval for t = 2.776 with sample size 5. express the answer as a percent.

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

Answer: NOTHING I JUST WANT THE 10 WITHDRAWED POINTS HAHAHAHAHAHAHAHAHAH

Step-by-step explanation:

NOTJIN

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Juan texts 20 messages in 5 minutes. At this rate how many text messages can he send in 30 minutes
pochemuha
<h2>Answer:</h2>

The answer 120 MESSAGES

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2 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME I DOUBTER UNDER HALf these questions Please help:(
Vaselesa [24]

Answer: I can only help you with number Im sorry

Step-by-step explanation:

10(-1.2 + 6) = 48

X = 3    Y = 2


-4 x 3 = -12    30 x 2 = 60


-12 + 60

48  


48 = 48

Im in middle school so Im sorry that it took me long to reply I had a hard time finding the answer. The other questions I haven’t been taught yet so maybe search up what the question is about for help if you don’t get any helpful replies :)(:

5 0
2 years ago
What does p equal please help me.
Sauron [17]

Answer: p < -3/5

Step-by-step explanation:

2p - 4 < -3p - 7

+3p       +3p

------------------------

5p - 4 < -7

     +4   +4

------------------------

5p < -3 (divide by 5)

p < -3/5

3 0
3 years ago
Solve x+7 &lt;4 with a line under the less sign
suter [353]
<span>x+7 <4 
Subtract 7 from both sides so that the only thing remaining on the left side is the x variable.
Final Answer: x<= -3</span>
3 0
3 years ago
Simplify the expression using trigonometric identities:
Anastaziya [24]

The simplified expression is the one in option B.

<h3>How to simplify the expression?</h3>

Remember that:

sec(x) = 1/cos(x)\\\\cos(x) = cos(-x)

With these two, we can rewrite the numerator as:

sec(x)*sin(-x) + tan(-x)\\\\\frac{1}{cos(x)}*sin(-x) + tan(x)\\\\\frac{1}{cos(-x)}*sin(-x) + tan(-x)\\\\2*tan(-x)

Replacing that in the given expression, we have:

\frac{2*tan(-x)}{1 + sec(-x)} = \frac{2*tan(-x)}{1 + 1/cos(-x)}

Now, if we multiply and divide by cos(-x), we get:

\frac{2*tan(-x)}{1 + 1/cos(-x)} =  \frac{2*tan(-x)}{1 + 1/cos(-x)}*\frac{cos(-x)}{cos(-x)} \\\\= \frac{2*sin(-x)}{1 + cos(-x)}

Now remember that:

cos(x) = cos(-x)\\sin(-x) = -sin(x)

With these two properties:

\frac{2*sin(-x)}{1 + cos(-x)} = \frac{-2*sin(x)}{1 + cos(x)}

Then the correct option is B.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

3 0
2 years ago
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