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3 years ago

8.

Mathematics

1 answer:

seropon [69]3 years ago

5 0

Answer:

I'm sorry I don't know the answer and I couldn't find it anywhere :(

Step-by-step explanation:

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A California licence plate consists of a sequence of seven symbols: number, letter, letter, letter, number, number, number, wher

tino4ka555 [31]

Answer:

There is a 44.73% probability that all symbols are different.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

There are 26 total letters and 10 total digits.

The plate has the following format:

number, letter, letter, letter, number, number, number

Total outcomes

Each number can have 10 values.

Each letter can have 26 values.

There are four numbers and 3 letters.

So there are

$10^{4}*26^{3} = 175760000$ possible plates

Desired outcomes

We cannot have repeated values.

So, for example, the first number can be any of the 10 digits. The second can be any of them, bar the first one. So 9 possible digits

The same logic for the letters, 26, then 25, then 24.

So there are

10*26*25*24*9*8*7 = 78624000 plates in which all symbols are different.

(a) What is the probability that all symbols are different

$P = \frac{78624000}{175760000} = 0.4473$

There is a 44.73% probability that all symbols are different.

7 0

3 years ago

The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did

Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

$P(A \, and \, B)= P(A)\times P(B\left | \right A )$

From the options, we have;

$P(fatigue \left | \right drug)$ = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)× $P(fatigue \left | \right drug)$

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0

3 years ago

Steve uses ⅜ gallon of paint to paint 4 identical birdhouses. How many gallons of paint does he use for each birdhouse? Plz hurr

Lelu [443]

Answer:

But of coarse, we need to set one up. 8/9 gallons of paint for 4 birdhouses. Divide 4 by both sides. Our answer is that for each birdhouse, he use about 0.22 gallons of paint. thank me later

3 0

3 years ago

–5x3y3 + 8x4y2 – xy5 – 2x2y4 + 8x6 + 3x2y4 – 6xy5 standard form

I am Lyosha [343]

Answer:

probably 8x6+8x4y2−5x3y3+x2y4−7xy5

Step-by-step explanation:

mathpapa lol idk i jus need points

4 0

3 years ago

Given l ∥ m ∥ n l∥m∥n, find the value of x.

Vikki [24]

Answer:

hfyfjcigdgicgxissrixlgxrisitfhlxhosgifohdgidyoft8dhoxgidtixitxtidr7dististisigsurarisotxyiisraurxgkyd

6 0

2 years ago