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alex41 [277]
3 years ago
10

A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 12 cm long and 4 cm wide. The di

ameter of each semicircle is the width of the rectangle. What is the area of the bookmark? Use 3.14 for TT.

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0
Working:
Area of the rectangle= 12 x 4 = 48cm^2
Area of the semicircles=
\pi x 2² = 12.56cm^2

48+12.56= 60.56

Answer:  60.56cm²
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Can someone help me here pls thanks!​
vesna_86 [32]

Using proportions, it is found that the measure of the inscribed angle B is of 30º.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In a circle, the inscribed angle is half the measure of the outside angle. Hence, in this problem, the measure of angle B is of 50% of 60º, hence:

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More can be learned about proportions at brainly.com/question/24372153

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4 0
2 years ago
"how many different rectangles" can you draw that have a perimeter of 12, 14
amm1812
Perimeter of rectangle = length + length + width + width

To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14

Rectangle with perimeter 12

Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3

Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have

Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have

The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12

length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------

Rectangle with perimeter of 14

Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14

Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14

Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14

We can have 3 different combinations of length and width





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Step-by-step explanation:

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Step-by-step explanation:

K equals 3 and so 15/3 equals 5.

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