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Nina [5.8K]
2 years ago
6

A store purchased a DVD for $12.00 and sold it to a customer for 50% more than the purchase price.The customer was charged a 7%

tax when the DVD was sold.What is the customer's total cost for the DVD?
Mathematics
2 answers:
Tems11 [23]2 years ago
3 0

Answer:

The customer's total cost for the DVD is $19.26

Step-by-step explanation:

Store buy the dvd for $12.00.

The store price is $12.00+50% more

The store price= $12.00 *(1+0.5)= $18.00

Final price (tax added)= $18.00 + 7%

Final price= $18.00 * (1 + 0.07)= $19.26

natita [175]2 years ago
3 0

Answer:

The total cost of the DVD for the consumer was 19.26 $

Step-by-step explanation:

The sales price for the DVD was the price paid by the store plus 50%. To discover this value we will transform the percentage in a real number, by dividing it by 100, like following:

50/100 = 0.5

We then multiply this value by the price paid by the store (12) to find out how much is 50% of that. Then we add this value to the price paid by the store and we obtain the price of the DVD before taxes. So we do as following:

Price before taxes = price paid by the store + (price paid by the store)*0.5

Price before taxes = 12 + 12*0.5 = 18 $

On top of that there was 7% of tax for the consumer. We must repeat the same steps as before but using 7 instead of 50. So we have:

Final price = Price before taxes + (Price before taxes)*(7/100)

Final price = 18 + 18*0.07 = 19.26 $

The total cost of the DVD for the consumer was 19.26 $

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Hi there! 

Your question: 

Sales fall from 300 per week to 270 per week what's the percentage change?

My answer:

The formula for calculating percent change is as follows: 

[(y2 - y1)/y1]*100=your percent change 

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Plug the numbers in: 

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Hope this helps! Let me know if it's incorrect so I can fix it:)
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<em>Comment on 3-4-5 triangle</em>

As you can see from the above, side measures of 3, 4, and 5 will form a right triangle. This is the smallest set of integers that will do so. It is also the ratios of the only set of side lengths in arithmetic progression that will do so.

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