How is constructing a perpendicular bisector similar to constructing an angle bisector? How is it different?

1 answer:

8 0

A perpendicular bisector literally bisect the perpendicular intersection in half the angle bisector is half of the angle. for example a 90 degree angle split in half is 45 degrees on both sides

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What's the weight/answer

DerKrebs [107]

I would assume that you convert 2.5 ounces into punds which would make it 0.15 lbs.

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3 years ago

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A candle shop sells scented candles for $16 each and unscented candles for $10 each. The shop sells 20 candles today and makes $

Amanda [17]

The system of equations becomes:

s + u = 28 This represent the number of candles sold
16s + 10u = 400 This represents the value of the candles sold

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3 years ago

Two forest service watchtowers spot a fire in the distance. The fire is 27 miles from Tower 2. About how far apart are the two w

Reptile [31]

Given that the two watchtowers spotted fire in the distance and watch tower 2 was 27 miles from the fire. Assuming that the fire is in the middle of both watch towers, then the distance between the two watch towers will be given by:
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3 years ago

Use the figure to find the specified angle measure. In the figure, m || n and x || y.

Tomtit [17]

Answer:

because m || n and x || y => ∠6 = ∠11 = 112°

Step-by-step explanation:

3 0

3 years ago

Find the sum of the first 17 terms of the arithmetic sequence 10, 14, 18, 22, 26...

kari74 [83]

10, 14, 18 ....

notice, we get the next term by simply adding 4 to the current term, thus "4" is the "common difference, and we know that 10 is the first term.

$\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=10\\
d=4\\
n=17
\end{cases}
\\\\\\
a_{17}=10+(17-1)(4)\implies a_{17}=10+(16)(4)
\\\\\\
a_{17}=10+64\implies a_{17}=74\\\\
-------------------------------$

$\bf \textit{ sum of a finite arithmetic sequence}
\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
a_1=10\\
a_{17}=74\\
n=17
\end{cases}
\\\\\\
S_{17}=\cfrac{17(10+74)}{2}\implies S_{17}=\cfrac{17(84)}{2}\implies S_{17}=714$

6 0

3 years ago

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