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3 years ago

Please help now with homework

Mathematics

1 answer:

damaskus [11]3 years ago

5 0

The correct answer is 1.25 dollars per pound. You can check it by multiplying it with 4.16

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Work out the percentage change to 2 decimal places when a price of £8.95 is increased to £10.

kicyunya [14]

Answer:

12% increase

Step-by-step explanation:

Divide the difference between the two prices by the original price:

1.05/8.95

= 0.12

So, the percent change is 12%

6 0

3 years ago

Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

ad-work [718]

<h3>Conner work is correct. Jana work is wrong</h3>

Solution:

Given that,

Conner and Jana are multiplying:

$(3^56^8)(3^96^{10})$

Given Conner's work is:

$(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}$

We have to check if this work is correct

Yes, Conner work is correct

From given,

$(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}$

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}$

Given Jana's work is:

$(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}$

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0

3 years ago

If U={1,2,3,4,5,6,7,8}, M={1,2,3,5} and N={2,4,6} find MUN compliment

nydimaria [60]

$M\cup N=\{1,2,3,4,5,6\}\\\\\overline{M\cup N}=\{7,8\}$

3 0

3 years ago

What is the value of n in the diagram below?

san4es73 [151]

Step-by-step explanation:

Picture############

5 0

3 years ago

Suppose that a study of elementary school students reports that the mean age at which children begin reading is 5.9 years with a

Bas_tet [7]

Answer:

5.9 years.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

Mean of the population is $\mu = 5.9$

If a sampling distribution is created using samples of the ages at which 69 children begin reading, what would be the mean of the sampling distribution of sample means?

By the Central Limit Theorem, the same population mean, of 5.9 years.

3 0

3 years ago