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3 years ago

13

Analyze a graph In Exercise,analyze and sketch the graph of the function.Label any relative extrema, points of inflation,and asy

mptotes.
f(x) = xe - x

1 answer:

FinnZ [79.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

Given is a function of x

$f(x) = xe^{-x}$

When y=0 we get x=0 and infinity

Hence x intercept is 0 and one asymptote is x axis.

When x=0 , y =0

$f'(x) = e^{-x}(-x+1)$

$f''(x) = e^{-x}(x-1-1)$

Maxima at x=1, and point of inflection is at x=2

Increasing upto x=1 and then decreases

Graph is enclosed

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I need help!!!! I don’t understand and it’s very confusing

irga5000 [103]

Answer:

C

Step-by-step explanation:

I explained in my last answer but someone deleted it

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3 years ago

What would the answer to this question be?<br> A. 40°<br> B. 60°<br> C. 80°<br> D. 100°

Alex777 [14]

Answer:

D. 100°

Step-by-step explanation:

A straight line is 180°. Add 50° and 30° (which is 80°) and subtract the total from 180°.

50 + 30 = 80

180 - 80 = 100

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3 years ago

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$2000 was borrowed for 4 years with an interest rate of 3% compounded annually. What is the total amount owed at the end of the

kompoz [17]

Answer:

$\$2,251.02$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the total amount owed

P is the amount of money borrowed

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=4\ years\\ P=\$2,000\\ r=3\%=3/100=0.03\\n=1$

substitute in the formula above

$A=2,000*(1+\frac{0.03}{1})^{1*4}$

$A=2,000*(1.03)^{4}$

$A=\$2,251.02$

4 0

3 years ago

Read 2 more answers

use the slope formula to find the slope of the line that goes through the points (5, 0) and (-5, 2). 0. -5. −15. undefined.

dsp73

Answer: The slope is 5.

Step-by-step explanation:

3 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago