Match each activity to the advantage it provides in reproduction. help me now
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We have given one graph which is plot between distance and time. where time is in minutes and distance is in seconds.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- For the first 5 minute ( O to A) , The distance is continously increasing 2m / per minute .
- For the 5 minute that is from 5 minute to 13 minute ( A to B) both marellize and her dog wally moving with the constant speed .
- For next 3 minutes that is from 10 minutes to 13 minutes ( B to C) , The distance is continously decreasing with time .
- For next 3 minutes that is from 13 to 16 minutes ( C to D) , Again they moved with constant speed .
- For next 6 minute that is from 16 to 21 minutes ( D to E) . Again, There distance is increasing with time .
- Again For next 4 minutes that is 21 to 25 minutes , they are moving with constant velocity .
1) Between O and A
- The marellize and wally when moving between O to A , The distance is constantly increasing with time.
- The graph is Straight line
2) Between A and B
- The marellize and wally when moving between A to B, The distance remains the same with time that is they moving with constant speed.
- The graph is constant or steady
3) Between B to C
- The marellize and wally when moving between B to C, The distance is constantly decreasing with time .
- The graph is straight line but it follows decreasing function .
4) For covering the First 6 km ,
<u>According </u><u>to </u><u>the </u><u>graph</u><u>, </u>
- For covering first 6 km, They took 3 minutes.
5) No, Marellize and wally walk does not from where they have started.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- It is end at 5 m instead of 0m .
Answer:
Step-by-step explanation:
If the solutions are x=-4 and x=3, then it must have factors (x+4)(x-3). Assuming there is no GCF or leading coefficient other than 1, multiply with FOIL to find the standard form.