Question

Which of the following is a solution of x² + 14x + 112 = 0? If necessary, round to the nearest hundredth.

Answer 1

To determine the solution of the quadratic equation, use the quadratic formula which states that,
                                x = ((-b  +/- sqrt (b² - 4ac)) / 2a
From the equation, a = 1, b = 14, and c = 112. Substituting these to the quadratic formula,
                               x = ((-14  +/- sqrt (14² - 4(1)(12)) / 2(1) = indeterminate
Thus, the equation does not a real number solution. 

Answer 2

Answer:

The given equation has no solution.

Step-by-step explanation:

Given the equation $x^2+14x+112=0$

we have to find the solution of the above equation.

The roots of quadratic equation $ax^2+bx+c=0$ is

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Equation : $x^2+14x+112=0$

The roots are

$x=\frac{-14\pm \sqrt{14^2-4(1)(112)}}{2}$      

$x=\frac{-14\pm \sqrt{196-448}}{2}=\frac{-14\pm \sqrt{-252}}{2}$      

Since, determinant under the root is negative

⇒ The given equation has no real solution.

Last option is correct.