All categories

3 years ago

Show that energy dissipated due to motion of a conductor in the magnetic field is due to mechanical energy.

Physics

1 answer:

avanturin [10]3 years ago

4 0

Explanation:

let us use the explanation below to get the intuition so desired;

According to Faraday's law of electro magnetic induction, when ever a coil/conductor is made to rotate in a magnetic field, voltage or emf is created and current is produced, in the long run energy has be produced or converted.

The conversion of this energy is made possible by the motion of the coil/conductor is the magnetic field, just by the motion of the conductor cutting through the magnetic field, thus creating electro motive force(E.M.F) hence producing current, and ultimately energy is created

You might be interested in

Oxygen at 50 lbf/in.2, 200 F is in a piston/cylinder arrangement with a volume of 4 ft3. It is now compressed in a polytropic pr

Ksju [112]

Answer:

The value of heat transfer during the process Q = - 29.49 KJ

Explanation:

Given data

$P_{1}$ = 50 $\frac{lbf}{in^{2} }$ = 344.7 k pa

$V_{1} = 4 ft^{3}$ = 0.113 $m^{3}$

$T_{1} = 200$ F = 366.4 K

$T_{2} = 400 F$ = 477.6 K

Poly tropic index n = 1.2

gas constant for oxygen = 0.26 $\frac{KJ}{kg K}$

From ideal gas equation

$P_{1}$ $V_{1}$ = m R $T_{1}$

Put all the values in above equation we get

⇒ 344.7 × 0.113 = m × 0.26 × 366.4

⇒ m = 0.408 kg

Heat transfer in poly tropic process is given by

Q = $\frac{\gamma - n}{( \gamma - 1)( n - 1)} [ {m R (T_{1} - T_{2} ) ]$

Put all the values in above formula we get

⇒ Q = $\frac{1.4 - 1.2}{( 1.4 - 1)( 1.2 - 1)} [ {m R (T_{1} - T_{2} ) ]$

⇒ Q = 2.5 × 0.408 × 0.26 × ( 366.4 - 477.6 )

⇒ Q = - 29.49 KJ

This is the value of heat transfer during the process & negative sign shows that heat is lost during the process.

3 0

4 years ago

As a candle burns on the table, you can see the electromagnetic energy and feel the thermal energy released. Which two statement

elena-s [515]

Answer:

The answer is B

Explanation:

3 0

3 years ago

Read 2 more answers

A hydrogen bond forms by the electrostatic interaction of opposite charges in two molecules. If

Darya [45]

The force between the molecules involved in the bond is 6. 426 *10^-11 Newton

<h3>How to determine the force</h3>

Using the formula:

F = K[q1 x q2]/D^2

where K is coulombs constant =9 *10 ^9 Nm^2/C^2.

q1 and q2 = charges = 1.60x10 -20C

d = distance between the charges = 2x10 -10 m

Substitute the values into the formula

F = $9 * 10^9\frac{ 1.60*10^ -20 * 1.60 *10^ -20}{2x10^ -10^{2} }$

F = $9 *10^9\frac{2. 856* 10^-40}{4* 10^-20}$

F = $9* 10^9 * 7. 14* 10^-21$

F = $6. 426 * 10^-11$ Newton

Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton

Learn more about electrostatic force here:

brainly.com/question/8424563

#SPJ1

5 0

2 years ago

When you push with a horizontal 15-N force on a book that slides at constant

Marat540 [252]

Answer:

f = 15 N

Explanation:

It is given that, when you push with a horizontal 15-N force on a book that slides at constant velocity, a frictional force also acts on it. Frictional force is an opposing force. The magnitude of applied force and frictional forces are same. So, the force of friction on the book is equal to 15 N.

8 0

3 years ago

Vector A has magnitude of 8units and makes an angle of 45° with the positive x-axis. Vector B also has the same magnitude of 8un

iragen [17]

Answer:

Explanation:

Because vectors have direction and x and y components you can't just add them and say that their length is 16 because A is 8 units and so is B. What you're actually finding is the magnitude and direction of the vector that results from this addition. The magnitude is the length of the resultant vector, which comes from the x and y components of A and B, and the direction is the angle between the resultant vector and the positive x axis. To add the vectors, then, we need to find the x and y components of each. We'll do the x components of A and B first so we can add them to get the x component of C. Since x values are directly related to cos, the formula to find the x components of vectors is

$V_x=Vcos\theta$ which is the magnitude of the vector (its length) and the angle. Finding the x components of A:

$A_x=8.0cos45$ so

$A_x=5.7$ and for B:

$B_x=8.0cos180$ since the negative x axis is the 180 degree axis and

$B_x=-8.0$ If we add them, we get

$C_x=-2.3$

Now onto the y components. The formula for that is almost the same as the x components except use sin instead of cos:

$A_y=8.0sin45$ so

$A_y=5.7$ and

$B_y=8.0sin180$ so

$B_y=0$ If we add them, we get

$C_y=5.7$

Now for the final magnitude:

$C_{mag}=\sqrt{(-2.3)^2+(5.7)^2}$ and

$C_{mag}=6.1 units$ and now onto the direction.

The x component of C is positive and the y component is negative, which means that the direction has us at an angle is quadrant 2; we add 180 to whatever the angle is. Finding the angle:

$tan^{-1}(\frac{C_y}{C_x})=(\frac{5.7}{-2.3})$ = -68 + 180 = 112 degrees

The resultant vector of A + B has a magnitude of 6.1 and a direction of 112°

Do the same thing for subtraction, except if you're subtracting B from A, the direction that B is pointing has to go the opposite way. That means that A doesn't change anything at all, but B is now pointing towards 0.

$A_x=5.7$ (doesn't change from above)

$B_x=8.0cos0$ and