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Ad libitum [116K]
2 years ago
11

what will be the focal lenght of a combined lens made by contact of two lenses of power +3D and -2D.​

Physics
1 answer:
4vir4ik [10]2 years ago
3 0
  • P_1=+3D
  • P_2=-2D

\\ \bull\tt\dashrightarrow P=P_1+P_2

\\ \bull\tt\dashrightarrow P=+3D-2D=+1D

Now

\\ \bull\tt\dashrightarrow f=\dfrac{1}{P}

\\ \bull\tt\dashrightarrow f=\dfrac{1}{1}

\\ \bull\tt\dashrightarrow f=1m

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In the diagram below, a heavy box is being lifted. What is the function of the pulley in this situation?
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3 years ago
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Countries with traditional economies are often less developed because:
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People are resistant to change, People have political freedom, Farmers institute new farming techniques and there is little need for medical facilities.
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2 years ago
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The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If
mafiozo [28]

Answer:

m=454.73 kg

Explanation:

To convert the energy of the cereal to know the weight:

m*g*h=Q'

Cal=0.0179*113 Cal=2.0227Cal

Q'=2.0227Cal*\frac{4186J}{1Cal}

m*g*h=8467.02J

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m=\frac{4456.33N}{9.8m/s^2}

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3 years ago
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If she can throw each rock with a speed of 7.5 m/s relative to the ground, causing the wagon to move, how many rocks must she th
Stels [109]

Complete question:

A child sits in a wagon with a pile of 0.64-kg rocks. If she can throw each rock with a speed of 7.5 m/s relative to the ground, causing the wagon to move, how many rocks must she throw per minute to maintain a constant average speed against a 3.9-N force of friction

Answer:

The number of rocks per minutes thrown is 49 rocks/min

Explanation:

Given;

mass of the rock, m = 0.64 kg

speed of the rock, v = 7.5 m/s

frictional force, f_k = 3.9 N

For an object to move at a constant speed, the applied force must be equal to the frictional force.

f_k = N(F_a)\\\\f_k = N(\frac{mv}{t})\\\\f_k = \frac{N}{t} (mv)\\\\\frac{N}{t} = \frac{f_k}{mv}

where;

F_a is the applied force

N/t is the number of rocks per minutes thrown

Substitute the given parameters;

\frac{N}{t} = \frac{f_k}{mv}\\\\ \frac{N}{t} = \frac{3.9}{0.64*7.5}\\\\ \frac{N}{t} = 0.8125 \ \frac{rocks}{second} * \frac{60 \ seconds}{1 \ min} = 48.75 \ \frac{rocks}{min}  \

Approximately 49 rocks/min

5 0
3 years ago
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