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den301095 [7]
3 years ago
6

If the particle has mass m, how fast must it be moving away from the Sun's center of mass to escape the gravitational influence

of the Sun? Express your answer to two significant digits and include the appropriate units.
Physics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

Explanation:

M = 1.989 x 10^30 kg

R = 6.96 x 10^8 m

G = 6.67 x 10^-11 Nm²/kg²

Let the velocity is v.

v=\sqrt{\frac{2GM}{R}}

v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 1.989\times 10^{30}}{6.96\times 10^{8}}}

v = 6.17 x 10^5 m/s

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An air balloon is moving upward at a constant speed of 3 m/s. Suddenly a passenger realizes that she left her camera on the grou
frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

speed of balloon is u=3\ m/s

speed of camera u_1=20\ m/s

Initial separation between camera and balloon is d_o=5\ m

Suppose after t sec of  throw camera reach balloon then,

distance travel by balloon is

s=ut

s=3\times t

and distance travel by camera to reach balloon is

s_1=ut+\frac{1}{2}at^2

s_1=20\times t-\frac{1}{2}gt^2

Now

\Rightarrow s_1=5+s

\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t

\Rightarrow 5t^2-17t+5=0

\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}

\Rightarrow t=\dfrac{17\pm 13.747}{10}

\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is  t=0.3253\ s

velocity is given by

v=u+at

v=20-10\times 0.3253

v=16.747\ m/s

and position of camera is same as of balloon so

Position is =5+3\times 0.3253

=5.975\approx 6\ m

8 0
3 years ago
A car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s per second. The curve has a radiu
IrinaK [193]
The centripetal force is:
 F = mv² / R
 Where:
 m: mass of the object
 v: object speed
 R: radius of the curve.
 We have to:
 m = 2000kg
 v = 25 m / s
 R = 80 meters.
 Then the centripetal force acting on the vehicle is:
 F = (2000kg * (25m / s) ²) / 80m
 F = 15625 N
4 0
3 years ago
Which is an example of radiation? Check all 
vampirchik [111]

Answer:

Explanation:

Examples are;

Ultraviolet light from sun.

Heat from a stove burner.

X-ray from an x-ray machine.

Alpha particle emit from a radio active decay of uranium.

Sound waves from your stereo.

Microwave from micro oven.

ultraviolet light from a black light.

Gamma radiations from a supernova.

AND MANY MORE.

8 0
3 years ago
Read 2 more answers
Suppose that two point charges, each with a charge of +3.00 Coulomb are separated by a distance of 3.00 meters. Determine the ma
Sveta_85 [38]

Answer:

9\cdot 10^9 N

Explanation:

The magnitude of the electrical force between the two point charges is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q_1 =q_2 = +3.0 C is the magnitude of each charge

r = 3.00 m is the separation between the two charges

Substituting the numbers into the formula, we find

F=(9\cdot 10^9 Nm^2C^{-2})\frac{(+3 C)^2}{(3.00 m)^2}=9\cdot 10^9 N

3 0
3 years ago
How many earth years does it take mars to orbit the sun
Colt1911 [192]

This is a question that would have literally have taken two seconds to look up on google but the answer is 1.88 years.

4 0
2 years ago
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