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nadezda [96]
3 years ago
11

(√2-3)(√2+3) what is this?

Mathematics
2 answers:
shutvik [7]3 years ago
7 0

Answer:

-1

Step-by-step explanation:

sqrt(2-3) x sqrt(2-3)= sqrt(-1)^2 = -1

Gekata [30.6K]3 years ago
6 0

Answer:

sqrt(2-3) x sqrt(2-3)= sqrt(-1)^2 = -1

maar rekenmachine zegt -7

Step-by-step explanation:

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Si el lado de un cuadrado mide 10cm cuanto mide él área del círculo que se encuentra adentro de ese cuadrado
Alex17521 [72]

Answer:

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

Step-by-step explanation:

Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.

Ahora nos fijamos que necesitamos saber para calcular el área de un circulo

a = área

r = radio

π = 3.14

a = π * r²

como podemos ver no sabemos el valor del radio

como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.

Entonces tenemos que dividir un lado por 2

10cm/2 = 5cm

El radio del circulo sera 5cm

Ahora que tenemos todos los datos podemos calcular el valor del área

a = 3.14 * (5cm)²

a = 3.14 * 25cm²

a = 78.5cm²

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

8 0
3 years ago
Oduct of (x2 + 3)(x - 5).
Zanzabum

Answer: 2x^2-7x-15

Step-by-step explanation:

reorder the terms (x*2+3)*(x-5)

multiply the parentheses

(2x+3)*(x-5)

collect like terms (2x^2-10x+3x-15)

product= 2x^2-7x-15

8 0
3 years ago
Plz help ma :/<br><br><br> Helpppppppppppppppppppppp
Marizza181 [45]

Answer:

It is 432

Step-by-step explanation:

6 0
3 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
Write the number in expanded form 637
Alexxandr [17]
600+30+7 if that is what you meant...
4 0
3 years ago
Read 2 more answers
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