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nadezda [96]
3 years ago
11

(√2-3)(√2+3) what is this?

Mathematics
2 answers:
shutvik [7]3 years ago
7 0

Answer:

-1

Step-by-step explanation:

sqrt(2-3) x sqrt(2-3)= sqrt(-1)^2 = -1

Gekata [30.6K]3 years ago
6 0

Answer:

sqrt(2-3) x sqrt(2-3)= sqrt(-1)^2 = -1

maar rekenmachine zegt -7

Step-by-step explanation:

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Find the mode of the following set of data:<br> 5, 8, 2, 5, 2,5<br> A 5<br> B) 2<br> C 2 and 5
Mandarinka [93]

Answer:

A  5   is the mode of the data

3 0
3 years ago
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Can someone solve this! Need it done soon
Airida [17]

Answer:

117.5 ft²

Step-by-step explanation:

To find the area of the shaded area, we can find the area of the square, then subtract the areas of the two semicircles.

First, we will find the area of the given square, by using the formula lw, multiplying the length and width. The dimensions of this square are 14×14.

14 · 14 = 196

The area of the square is 196 ft².

We can now find the area of the two congruent half-circles. Since they are identical, we can simply find the area of one circle if it was whole. To find the area of a circle, we'll use the formula A=\pi r^2. With some simple deduction, we can see that the diameter of the circle is 10 ft, so the radius would be 5 ft long. Plug our values into the formula.

A = \pi5²

We will use 3.14 for \pi.

A = 78.5

The area of both the semicircles is 78.5 ft².

Now, we can subtract.

196 - 78.5 = 117.5

The area of the figure is 117.5 ft².

Good luck ^^

7 0
3 years ago
27
katrin2010 [14]

Answer:

A  ≈ 35.3 units²

Step-by-step explanation:

Calculate the radius CB using Pythagoras' identity in the right triangle.

CB² + AB² = AC²

CB² + 6² = 9²

CB² + 36 = 81 ( subtract 36 from both sides )

CB²  = 45 = r²

Then area of quarter circle is

A = \frac{1}{4} × πr² = \frac{1}{4} × π × 45 ≈ 35.3

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3 years ago
What is 4,226 - 2,958
Vinvika [58]

Answer:

1,268

Step-by-step explanation:

8 0
3 years ago
Y = 1/2x -4 plz show the graph, I really need to know! But it's 8th grade math!
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Answer:

(-4, 8)

Step-by-step explanation:

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3 years ago
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