39=1/2h = 78=h 52=(1/2 78)6+7 = 52=39+13
Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is

Using this formula, we get


and


Now, area of the quadrilateral is



Therefore, the area of the quadrilateral is 34 cm².
Answer: a. Each term in Bill's pattern is twice the value of the corresponding item in Jan's pattern.
Step-by-step explanation:
Jan created a pattern by adding 3 and Bill created a pattern by adding 6.
6 is twice the value of 3 so Bill's terms will be twice the value of Jan's corresponding terms as well.
To prove it:
12 is twice the value of 6
18 is twice the value of 9
24 is twice the value of 12
Amount to be paid back = $ 88,624.36
<u>Step-by-step explanation:</u>
Principal amount = $ 40,000
Rate of interest = 7.5%
Number of years = 11

Plugin the values as,



