The midpoint formula is basically (averaging the x coordinates, averaging the y coordinates).
Point A: (3, 7)
Point B: (2, -1)
Midpoint x: (3 + 2) / 2 = 5 / 2
Mindpoint y: (7 - 1) / 2 = 3
Therefore, the midpoint of the segment is choice C (5/2, 3)
Answering pretty sure yes
Step-by-step explanation:
In pure translation or in roll without slip?
In pure translation, just use Fnet = m*a. Fnet = 7.5 Newtons
In roll without slip it has effectively more inertia than 5 kilograms. The effective inertia can be found as:
m_effective = m + I/r^2
For a uniform solid sphere, I = 2/5*m*r^2
So m_effective = 7/5*m
To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).
i hope this is what ur looking for
