Answer:
4x-8+4y
Step-by-step explanation:
Answer:
As follows,
Step-by-step explanation:
Find the attachment.
Distance of PQ=√13
Distance of QR=√13
Distance of PR=√26
Thus, PQR is an isosceles triangle.
Distance of MN=√(16+(a-2)^2)
16=16+a^2-4a+4
a^2-4a+4=0
a=2
Distance of RS=√(9+(b+1)^2)
25=9+b^2+2b+1
b=3 or -5
Distance of RS=√(9+(-1-c)^2)
18=9+c^2 + 2 c + 1
c=-4,2
This question was not written properly
Complete Question
Find the minimum value of the function f(x) = 0.9x² + 3.42x - 2.4 to the nearest
hundredth.
Answer:
The minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
Step-by-step explanation:
Our quadratic equation =
ax² + bx + c
f(x) = 0.9x² + 3.42x - 2.4
The minimum value of x formula=
x = -b/2a
a = 0.9
b = 3.42
x = -3.42/2 × 0.9
x = -3.42/1.8
x = -1.9
We input the value x in order to get the minimum value of y
f(x) = y
f(x) = 0.9x² + 3.42x - 2.4
f(-1.9) = 0.9(-1.9)² + 3.42(-1.9) - 2.4
= 3.249 - 6.498 - 2.4
=3.249 - 8.898
= -5.649
Approximately to the nearest hundredth = -5.65
Therefore, the minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
Surface are = [(3*4) + (3*5) + (4*5)] *2 calculate as 94 squat inches
Answer:
Y= X/3 + 10
Step-by-step explanation:
The initial time of departure = 4.00pm
Her flight was then delayed for 10 minutes
Let the initial flight plan be X
Let the new flight plan be Y
The new flight plan allows her arrive at her destination three times faster. this means Y = (1/3)X
Y = X/3
The equation to know the number of minutes after 4.00pm she will arrive is
1/3 of the initial plan + the 10 minutes of delay
Y = X/3 +10
