Answer:
Mistake in Line 2
Step-by-step explanation:
Line 1
7(6) ÷ 5 + 42
Line 2
7(6) ÷ 5 + 16
Line 3
42 ÷ 5 + 16
Line 4
42 ÷ 21
Line 5
2
To simplify any expression we use order of operation
Line 1 is 7(6) ÷ 5 + 42
Order of operation is PEMDAS
First we start with parenthesis
so we multiply 7(6) in line 2
7*6- 42
So Line 2 is 42 ÷ 5 + 42
Hence there is a mistake in Line 2
Answer:
Answer below
Step-by-step explanation:
Point D: (-6,-1)
Point C: (-3,0)
Point B: (-3,6)
Point A: (0,0)
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement. Yes, there is a "relationship" regarding the tangent of the two acute angles (A and B) in a right triangle.
Freezing point of nitro : -210
freezing point of mercury : 171 degrees higher......so we add
-210 + 171 = - 39 c
