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Answer:
Option D
Step-by-step explanation:
Properties of a rhombus,
1). Diagonals of a rhombus bisect the opposite angles.
2). Sum of adjacent two angles of a rhombus is 180°.
By property (1),
Diagonal JL will bisect the angles ∠MJK and ∠KLM.
Therefore, m∠KLM = 2(5x + 3)°
Similarly, diagonal KM will bisect the angles ∠JKL and JML.
Therefore, m∠JKL = 2(9x - 11)°
By property (2),
2(9x - 11)° + 2(5x + 3)° = 180°
9x - 11 + 5x + 3 = 90
14x - 8 = 90
14x = 98
x = 7
Since, m∠KLM = 2(5x + 3)°
= 2(5×7 + 3)°
= 76°
Therefore, Option D will be the answer.
Answer: -7cos(x)
Step-by-step explanation:
d/dx (f(x))= -7cos(x)
The algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z
<h3>How to write an algebraic expression for the word phrase "the product of a number and 3" as a variable expression?</h3>
The word phrase is given as:
"the product of a number and 3"
Represent the number with z
So, the word phrase can be rewritten as:
"the product of a number z and 3"
The product of a number z and 3 is represented as:
z * 3
When evaluated,, the expression becomes
z * 3 = 3z
Hence, the algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z
Read more about algebraic expression at
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Answer:
C. log 9
Step-by-step explanation:
Hope this helped!
