Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
In 6.23 * 10^23 atoms, number of moles = 1
So, It would be: 3.94 * 10^23 / 6.23 * 10^23
= 0.654 moles
In short, Your Answer would be Option A
Hope this helps!
True precise and accurate are the same thing
Answer:
Avogadro's number
Explanation:
Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
It means 1 mole of any substance contain 6.022 × 10²³ number of representative particles.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
35.45 g Cl⁻ = 1mole = 6.022 × 10²³ Cl⁻ ions
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen