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Mars2501 [29]
3 years ago
7

What is the compound MnCl2 called?

Chemistry
1 answer:
givi [52]3 years ago
8 0

Answer is Manganese(ii) chloride

To answer this, you need to know the charges for both Mn and Cl

Mn is in the transition metal category and is unique with having 3 levels of charges

manganese - MN

Manganese(ii) - Mn^2+

Manganese(iii) - Mn^3+


Cl is a nonmetal with the standard charge of Cl^-1

Since you have two charges that don't cancel out, they get switched.

So Cl would receive a positive 2. Because it was a positive 2, we can assume that it starts with Manganese(ii). Then we add chloride to the end of it as it ends with Cl.

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Which of the solutions have greatest osmotic pressure 30% sucrose 60% sucrose or 30% magnesium sulfate?
timofeeve [1]

Answer:Osmotic pressure is the minimum amount of pressure a solution must exert in order to prevent from crossing a barrier by osmosis. Solute molecules have difficulty crossing semipermeable membranes, so the more solutes that are in a solution, the higher the osmotic pressure will be. Between 30% sucrose and 60% sucrose, 60% sucrose will have a greater osmotic pressure than 30% because it has a higher percentage of solutes. However, since sucrose has a higher potential to cross semipermeable membranes and is more absorbable than magnesium sulfate, magnesium sulfate would have a higher osmotic pressure than 60% sucrose even though 60% sucrose has higher molecules.

Explanation:

8 0
3 years ago
For the following reaction,
jeka94

Answer:

The answer to your question is:

1.- CO

2.- 0.414 moles of CO2

Explanation:

Data

                               2CO   + O2      ⇒    2CO2

CO = 0.414 moles

O2 = 0.418

 

Process

theoretical ratio   CO/O2 = 2/1 = 1

experimental ratio  CO/O2 = 0.414/0.418 = 0.99

Then the limiting reactant is CO

2.-

                    2 moles of CO ---------------  2 moles of CO2

                    0.414 moles of CO ---------  x

                   x = (0.414 x 2) / 2

                   x = 0.414 moles of CO2

                   

5 0
3 years ago
what is the kinetic energy of the emitted electrons when cesium is exposed to uv rays of frequency 1.4×1015hz?
Anika [276]
<span>The equation you used is KE=hv-hv0, where h=6.63*10^-34 (constant). You multiply h by 1.5*10^15. Multiply h by the threshold freq of cesium (from part A). Subtract the second answer from the first answer, and you get the kinetic energy. Hope this helps.</span>
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Samira has two pens. She wants to know which pen was used to write a note. She labels her pens A and B. She puts a sample of ink
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Answer:

b

Explanation:

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3. What is the name of the technique used to weigh the unknown liquid in part A of the
Anna [14]

Answer:

The technique is called weighing by difference

7 0
3 years ago
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